Is there a difference between casting to an array and using this function?
For instance, if we have:
$arrayObject = new ArrayObject([1, 2, 3]);
Is there a difference between these:
$array = (array) $arrayObject;
vs
$array = $arrayObject->getArrayCopy();
If not, is there any scenario where they would produce different results, or do they produce the result in different ways?
ArrayObject::getArrayCopy
(PHP 5, PHP 7, PHP 8)
ArrayObject::getArrayCopy — Crea una copia de la clase ArrayObject
Parámetros
Esta función no tiene parámetros.
Valores devueltos
Devuelve una copia del array. Cuando la clase ArrayObject hace referencia a un objeto, un array de las propiedades públicas del objeto que será devuelto.
Ejemplos
Ejemplo #1 ArrayObject::getArrayCopy() example
<?php
// Array de frutas
$fruits = array("limones" => 1, "naranjas" => 4, "bananas" => 5, "manzanas" => 10);
$fruitsArrayObject = new ArrayObject($fruits);
$fruitsArrayObject['peras'] = 4;
// crear una copia del array
$copy = $fruitsArrayObject->getArrayCopy();
print_r($copy);
?>El resultado del ejemplo sería:
Array
(
[limones] => 1
[naranjas] => 4
[bananas] => 5
[manzanas] => 10
[peras] => 4
)
add a note
User Contributed Notes 5 notes
jlshor at buffalo dot edu ¶
8 years ago
Ivo von Putzer ¶
13 years ago
If you did something like this to make your constructor multidimensional capable you will have some trouble using getArrayCopy to get a plain array straight out of the method:
<?php
public function __construct( $array = array(), $flags = 2 )
{
// let’s give the objects the right and not the inherited name
$class = get_class($this);
foreach($array as $offset => $value)
$this->offsetSet($offset, is_array($value) ? new $class($value) : $value);
$this->setFlags($flags);
}
?>
That’s the way I solved it:
<?php
public function getArray($recursion = false)
{
// just in case the object might be multidimensional
if ( $this === true)
return $this->getArrayCopy();
return array_map( function($item){
return is_object($item) ? $item->getArray(true) : $item;
}, $this->getArrayCopy() );
}
?>
Hope this was useful!
spidgorny at gmail dot com ¶
8 years ago
<?php
$data = $likeArray->getArrayCopy();
?>
will NOT be magically called if you cast to array. Although I've expected it.
<?php
$nothing = (array)$likeArray;
?>
Here, $data != $nothing.
sorcerer ¶
7 years ago
When I used print_r ($fruitsArrayObject) instead of print_r ($copy), i.e. ignoring the getArrayCopy() step, I still got the same output. Why?
php at webflips dot net ¶
10 years ago
"When the ArrayObject refers to an object an array of the public properties of that object will be returned."
This description does not seem to be right:
<?php
class A
{
public $var = 'var';
protected $foo = 'foo';
private $bar = 'bar';
}
$o = new ArrayObject(new A());
var_dump($o->getArrayCopy());
/*
Dumps:
array(3) {
["var"]=>
string(3) "var"
["*foo"]=>
string(3) "foo"
["Abar"]=>
string(3) "bar"
}
*/
?>
So it does not only include the public properties.
