Edit Report a Bug

DateInterval::__construct

(PHP 5 >= 5.3.0, PHP 7, PHP 8)

DateInterval::__construct — Crea un nuevo objeto DateInterval

Descripción

public DateInterval::__construct(string $interval_spec)

Crea un nuevo objeto DateInterval.

Parámetros

interval_spec

Una especificación de intervalo.

El formato empieza con la letra P, de periodo. Cada periodo de duración está representado por un valor de tipo integer seguido de un indicador de periodo. Si la duración contiene elementos de hora, esa parte de la especificación estará precedida por una letra T.

**Indicadores de periodo de `interval_spec`**
Indicador de periodo	Descripción
`Y`	años
`M`	meses
`D`	días
`W`	semanas; estas se convierten a días, Antes de PHP 8.0.0, no se puede combinar con `D`.
`H`	horas
`M`	minutos
`S`	segundos

Algunos ejemplos sencillos: Dos días es P2D. Dos segundos es PT2S. Seis años y cinco minutos es P6YT5M.

Nota:
Los tipos de unidades deben ser escritos desde la unidad de escala más grande a la izquierda a la unidad de escala más pequeña a la derecha. Así los años van antes que los meses, meses antes que días, días antes que minutos, etc. Así un año y cuatro días debe representarse como P1Y4D, y no como P4D1Y.

La especificación también puede ser representada como una fecha/hora. Un ejemplo de un año y cuatro días sería P0001-00-04T00:00:00. Pero los valores en este formato no pueden exceder el punto de desbordamiento de un periodo (p.ej. 25 horas no es válido).

Estos formatos están basados en la » especificación de duración ISO 8601.

Errores/Excepciones

Lanza una Exception cuando el interval_spec no puede ser analizado como un intervalo.

Historial de cambios

Versión	Descripción
8.0.0	`W` se puede combinar con `D`.

Ejemplos

Ejemplo #1 Ejemplo de DateInterval

<?php

$intervalo = new DateInterval('P1W2D');
var_dump($intervalo);

?>

Output of the above example in PHP 8:

object(DateInterval)#1 (16) {
  ["y"]=>
  int(0)
  ["m"]=>
  int(0)
  ["d"]=>
  int(9)
  ["h"]=>
  int(0)
  ["i"]=>
  int(0)
  ["s"]=>
  int(0)
  ["f"]=>
  float(0)
  ["weekday"]=>
  int(0)
  ["weekday_behavior"]=>
  int(0)
  ["first_last_day_of"]=>
  int(0)
  ["invert"]=>
  int(0)
  ["days"]=>
  bool(false)
  ["special_type"]=>
  int(0)
  ["special_amount"]=>
  int(0)
  ["have_weekday_relative"]=>
  int(0)
  ["have_special_relative"]=>
  int(0)
}

Salida del ejemplo anterior en PHP 7:

object(DateInterval)#1 (16) {
  ["y"]=>
  int(0)
  ["m"]=>
  int(0)
  ["d"]=>
  int(2)
  ["h"]=>
  int(0)
  ["i"]=>
  int(0)
  ["s"]=>
  int(0)
  ["f"]=>
  float(0)
  ["weekday"]=>
  int(0)
  ["weekday_behavior"]=>
  int(0)
  ["first_last_day_of"]=>
  int(0)
  ["invert"]=>
  int(0)
  ["days"]=>
  bool(false)
  ["special_type"]=>
  int(0)
  ["special_amount"]=>
  int(0)
  ["have_weekday_relative"]=>
  int(0)
  ["have_special_relative"]=>
  int(0)
}

Ver también

DateInterval::format() - Formatea el intervalo
DateTime::add() - Añade una cantidad de días, meses, años, horas, minutos y segundos a un objeto DateTime
DateTime::sub() - Sustrae una cantidad de días, meses, años, horas, minutos y segundos de un objeto DateTime
DateTime::diff() - Devuelve la diferencia entre dos objetos DateTime

add a note

User Contributed Notes 15 notes

down

102

owen at beliefs.com ¶

11 years ago


M is used to indicate both months and minutes.

As noted on the referenced wikipedia page for ISO 6801 http://en.wikipedia.org/wiki/Iso8601#Durations

To resolve ambiguity, "P1M" is a one-month duration and "PT1M" is a one-minute duration (note the time designator, T, that precedes the time value).

Using: PHP 5.3.2-1ubuntu4.19

// For 3 Months
$dateTime = new DateTime;echo $dateTime->format( DateTime::ISO8601 ), PHP_EOL;
$dateTime->add(new DateInterval("P3M"));
echo $dateTime->format( DateTime::ISO8601 ), PHP_EOL;
Results in:
2013-07-11T11:12:26-0400
2013-10-11T11:12:26-0400

// For 3 Minutes
$dateTime = new DateTime;echo $dateTime->format( DateTime::ISO8601 ), PHP_EOL;
$dateTime->add(new DateInterval("PT3M"));
echo $dateTime->format( DateTime::ISO8601 ), PHP_EOL;
Results in:
2013-07-11T11:12:42-0400
2013-07-11T11:15:42-0400

Insert a T after the P in the interval to add 3 minutes instead of 3 months.

down

Hernanibus ¶

7 years ago


It is not stated, but you cannot create directly a negative interval, this is you cannot create a "-2 days" interval as:

<?
$interval = new DateInterval("P-2D");//or
$interval = new DateInterval("-P2D");
?>

Instead you have to create first the interval and then set its 'invert' property to 1, this is:

<?
$interval = new DateInterval("P2D");
$interval->invert = 1;
?>

Then you should keep in mind that this interval acts as a negative number, hence to subtract the interval from a given date you must 'add' it:

<?
$interval = new DateInterval("P2D");
$interval->invert = 1;
$date       = new DateTime ("1978-01-23 17:46:00");
$date->add($interval)->format("Y-m-d H:i:s");//this is "1978-01-21 17:46:00"
?>

down

kuzb ¶

13 years ago


It should be noted that this class will not calculate days/hours/minutes/seconds etc given a value in a single denomination of time.  For example:

<?php
    $di = new DateInterval('PT3600S');
    echo $di->format('%H:%i:%s');
    
?>

will yield 0:0:3600 instead of the expected 1:0:0

down

buvinghausen at gmail dot com ¶

12 years ago


I think it is easiest if you would just use the sub method on the DateTime class.

<?php
$date = new DateTime();
$date->sub(new DateInterval("P89D"));

down

admin at torntech dot com ¶

9 years ago


Warning - despite the $interval_spec accepting the ISO 8601 specification format, it does not accept decimal fraction values with period or comma as stated in the specification.

https://bugs.php.net/bug.php?id=53831

<?php
/* Example from ISO 8601 documentation */
$interval = new DateInterval('P0.5Y');
?>

Will result in
Fatal error: Uncaught exception 'Exception' with message 'DateInterval::__construct(): Unknown or bad format (P0.5Y)'

down

kevinpeno at gmail dot com ¶

13 years ago


Note that, while a DateInterval object has an $invert property, you cannot supply a negative directly to the constructor similar to specifying a negative in XSD ("-P1Y"). You will get an exception through if you do this. 

Instead you need to construct using a positive interval ("P1Y") and the specify the $invert property === 1.

down

userexamplecom at mailinator dot com ¶

8 years ago


Take care, if you have a DateTime Object on the 31h of January and add Da DateInterval of one Month, then you are in March instead of February.

For Example:
---
// given the actual date is 2017-01-31
$today = new DateTime('now', $timeZoneObject);
$today->add(new DateInterval('P1M'));
echo $today->format('m');
// output: 03
---

down

daniellehr at gmx dot de ¶

12 years ago


Alternatively you can use DateInterval::createFromDateString() for negative intervals:

<?php
$date = new DateTime();
$date->add(DateInterval::createFromDateString('-89 days'));

down

jawzx01 at gmail dot com ¶

12 years ago


As previously mentioned, to do a negative DateInterval object, you'd code: 



<?php

$date1 = new DateTime();

$eightynine_days_ago = new DateInterval( "P89D" );

$eightynine_days_ago->invert = 1; //Make it negative. 

$date1->add( $eightynine_days_ago );

?>



and then $date1 is now 89 days in the past.

down

sloanlance+php.net gmail com ¶

6 years ago


⚠️ It's important to remember the warning about DateInterval given by "admin at torntech dot com" in an earlier comment (http://php.net/manual/en/dateinterval.construct.php#116750).  To reiterate:

Some versions of PHP (e.g., 5.6.31) have a bug that disallows fractional parts in a ISO 8601 duration string given as the argument for the DateInterval constructor.  That is, these examples will fail:

<?php
// 'P0.5Y' is valid according to ISO 8601
$interval = new DateInterval('P0.5Y');  // Throws exception
?>

<?php
// 'PT585.829S' is valid according to ISO 8601
$interval = new DateInterval('PT585.829S');  // Throws exception
?>

If this bug affects you, please go to the report for this bug in the PHP Bug Tracking System, and place a vote stating that it affects you:  https://bugs.php.net/bug.php?id=53831

down

lsloan-php dot net at umich dot edu ¶

8 years ago


Although PHP refers to periods of time as "intervals", ISO 8601 refers to them as "durations".  In ISO 8601, "intervals" are something else.

While ISO 8601 allows fractions for all parts of a duration (e.g., "P0.5Y"), DateInterval does not.  Use caution when calculating durations.  If the duration has a fractional part, it may be lost when storing it in a DateInterval object.

down

Anonymous ¶

3 years ago


Note that to add time you must enter P even though the period is empty.

To add 1 hour : 

<?php

$plusOneHour = (new DateTime('now'))->add(new DateInterval("PT1H"));

var_dump($plusOneHour);

?>

down

Ray.Paseur sometimes uses Gmail ¶

8 years ago


To recover the interval specification string:

<?php
function get_interval_spec(DateTime $alpha, DateTime $omega)
{
    $intvl = $alpha->diff($omega);

    $date = NULL;
    if ($intvl->y) $date .= $intvl->y . 'Y';
    if ($intvl->m) $date .= $intvl->m . 'M';
    if ($intvl->d) $date .= $intvl->d . 'D';

    $time = NULL;
    if ($intvl->h) $time .= $intvl->h . 'H';
    if ($intvl->i) $time .= $intvl->i . 'M';
    if ($intvl->s) $time .= $intvl->s . 'S';
    if ($time) $time = 'T' . $time;

    $text ='P' . $date . $time;
    if ($text == 'P') return 'PT0S';
    return $text;
}

down

-1

grzeniufication ¶

4 years ago


If you'd like to persist an interval object in a DB it could be handy to implement the __toString() method. A formatted interval value can be easier to read by a human than the output of serialize. Here's an example:

<?php

namespace App;

class DateInterval extends \DateInterval
{
    public function __toString()
    {
        return $this->format('P%yY%mM%dDT%hH%iM%sS');
    }
}

$interval1 = new DateInterval('P1Y');
$interval2 = new DateInterval(strval($interval1));
assert($interval1 == $interval2);

down

-17

bkilinc at deyta dot net ¶

10 years ago


interval_spec Period Designators, has two 'M's for months and minutes.

add a note