If you want to get the real name of the file without the directory name, you can just use the function basename() as the follow:
<?
$zip_dir = "./import/";
$zip = zip_open($zip_dir."import.zip");
if ($zip) {
while ($zip_entry = zip_read($zip)) {
$file = basename(zip_entry_name($zip_entry));
$fp = fopen($zip_dir.basename($file), "w+");
if (zip_entry_open($zip, $zip_entry, "r")) {
$buf = zip_entry_read($zip_entry, zip_entry_filesize($zip_entry));
zip_entry_close($zip_entry);
}
fwrite($fp, $buf);
fclose($fp);
echo "The file ".$file." was extracted to dir ".$zip_dir."\n<br>";
}
zip_close($zip);
}
?>
Thefore you can extract files without concern with the directory that is set inside the zip source.
Remember to give write permission (w) on that directory.
Hello from Brazil.
Leandro
zip_entry_name
(PHP 4 >= 4.1.0, PHP 5 >= 5.2.0, PHP 7, PHP 8, PECL zip >= 1.0.0)
zip_entry_name — Devuelve el nombre de la entrada de un directorio
Descripción
Devuelve el nombre de una entrada de directorio específica.
Valores devueltos
El nombre de la entrada de directorio.
Ver también
- zip_open() - Abre un fichero ZIP
- zip_read() - Leer la siguiente entrada en el fichero ZIP
add a note
User Contributed Notes 2 notes
leandro_dealmeida at hotmail dot com ¶
22 years ago
kevyn at opsone dot net ¶
16 years ago
Big note for filename with accents.
Some Zip softwares encode accents with CP850.
So use iconv for keeping your accents SAFE !
