mysqli_result::fetch_assoc

mysqli_fetch_assoc

(PHP 5, PHP 7, PHP 8)

mysqli_result::fetch_assoc -- mysqli_fetch_assocObtener una fila de resultado como un array asociativo

Descripción

Estilo orientado a objetos

mysqli_result::fetch_assoc(): array

Estilo por procedimientos

mysqli_fetch_assoc(mysqli_result $result): array

Retorna un array asociativo correspondiente a la fila obtenida o null si no hubiera más filas.

Nota: Los nombres de los campos devueltos por esta función son sensibles a mayúsculas y minúsculas.

Nota: Esta función define campos NULOS al valor null de PHP.

Parámetros

result

Sólo estilo por procedimientos: Un conjunto de identificadores de resultados devuelto por mysqli_query(), mysqli_store_result() o mysqli_use_result().

Valores devueltos

Devuelve un array asociativo de strings que representa a la fila obtenida del conjunto de resultados, donde cada clave del array representa el nombre de una de las columnas de éste; o null si no hubieran más filas en dicho conjunto de resultados.

Si dos o más columnas del resultado tienen el mismo nombre de campo, la última columna tomará precedencia. Para acceder a la/s otra/s columna/s con el mismo nombre, es necesario acceder al resultado ya sea usando los índices numéricos mediante mysqli_fetch_row(), ya sea añadiéndole alias a los campos.

Ejemplos

Ejemplo #1 Estilo orientado a objetos

<?php
$mysqli
= new mysqli("localhost", "mi_usuario", "mi_contraseña", "world");

/* verificar la conexión */
if ($mysqli->connect_errno) {
printf("Conexión fallida: %s\n", $mysqli->connect_error);
exit();
}

$consulta = "SELECT Name, CountryCode FROM City ORDER by ID DESC LIMIT 50,5";

if (
$resultado = $mysqli->query($consulta)) {

/* obtener un array asociativo */
while ($fila = $resultado->fetch_assoc()) {
printf ("%s (%s)\n", $fila["Name"], $fila["CountryCode"]);
}

/* liberar el conjunto de resultados */
$resultado->free();
}

/* cerrar la conexión */
$mysqli->close();
?>

Ejemplo #2 Estilo por procedimientos

<?php
$enlace
= mysqli_connect("localhost", "mi_usuario", "mi_contraseña", "world");

/* verificar la conexión */
if (mysqli_connect_errno()) {
printf("Conexión fallida: %s\n", mysqli_connect_error());
exit();
}

$consulta = "SELECT Name, CountryCode FROM City ORDER by ID DESC LIMIT 50,5";

if (
$resultado = mysqli_query($enlace, $consulta)) {

/* obtener array asociativo */
while ($row = mysqli_fetch_assoc($resultado)) {
printf ("%s (%s)\n", $row["Name"], $row["CountryCode"]);
}

/* liberar el conjunto de resultados */
mysqli_free_result($resultado);
}

/* cerrar la conexión */
mysqli_close($link);
?>

El resultado de los ejemplos sería:

Pueblo (USA)
Arvada (USA)
Cape Coral (USA)
Green Bay (USA)
Santa Clara (USA)

Ejemplo #3 Un ejemplo de mysqli_result comparando el uso de iterator

<?php
$c
= mysqli_connect('127.0.0.1','user', 'pass');

// Usando iteradores (el soporte fue añadido con PHP 5.4)
foreach ( $c->query('SELECT user,host FROM mysql.user') as $fila ) {
printf("'%s'@'%s'\n", $fila['user'], $fila['host']);
}

echo
"\n==================\n";

// Sin usar iteradores
$result = $c->query('SELECT user,host FROM mysql.user');
while (
$fila = $result->fetch_assoc()) {
printf("'%s'@'%s'\n", $fila['user'], $fila['host']);
}

?>

El resultado del ejemplo sería algo similar a:

'root'@'192.168.1.1'
'root'@'127.0.0.1'
'dude'@'localhost'
'lebowski'@'localhost'

==================

'root'@'192.168.1.1'
'root'@'127.0.0.1'
'dude'@'localhost'
'lebowski'@'localhost'

Ver también

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User Contributed Notes 6 notes

up
86
Miller
11 years ago
I often like to have my results sent elsewhere in the format of an array (although keep in mind that if you just plan on traversing through the array in another part of the script, this extra step is just a waste of time).

This is my one-liner for transforming a mysqli_result set into an array.
<?php
$sql
= new MySQLi($host, $username, $password, $database);

$result = $sql->query("SELECT * FROM `$table`;");
for (
$set = array (); $row = $result->fetch_assoc(); $set[] = $row);
print_r($set);
?>

Outputs:
Array
(
    [0] => Array
        (
            [id] => 1
            [field2] => a
            [field3] => b
        ),
    [1] => Array
        (
            [id] => 2
            [field2] => c
            [field3] => d
        )
)

I use other variations to adapt to the situation, i.e. if I am selecting only one field:
<?php
$sql
= new MySQLi($host, $username, $password, $database);
$result = $sql->query("SELECT `field2` FROM `$table`;");
for (
$set = array (); $row = $result->fetch_assoc(); $set[] = $row['field2']);
print_r($set);
?>
Outputs:
Array
(
    [0] => a
    [1] => c
)

Or, to make the array associative with the primary index (code assumes primary index is the first field in the table):
<?php
$sql
= new MySQLi($host, $username, $password, $database);
$result = $sql->query("SELECT * FROM `$table`;");
for (
$set = array (); $row = $result->fetch_assoc(); $set[array_shift($row)] = $row);
print_r($set);
?>
Outputs:
Array
(
    [1] => Array
        (
            [field2] => a
            [field3] => b
        ),
    [2] => Array
        (
            [field2] => c
            [field3] => d
        )
)
up
2
Enrique Garcia
1 year ago
There is a difference between MariaDB and MySQL(>5.4) whether the input parameter (mysqli object) has data or is empty (it comes from a previus query).
-MariaDB:  you get an exception:
Fatal error: Uncaught TypeError: mysqli_fetch_assoc(): Argument #1 ($result) must be of type mysqli_result
-MySQL: you can continue, in spite of not having data in the mysqli object.
up
28
james dot phx at gmail dot com
13 years ago
IMPORTANT NOTE:

If you were used to using code like this:

<?php
while(false !== ($row = mysql_fetch_assoc($result)))
{
   
//...
}
?>

You must change it to this for mysqli:

<?php
while(null !== ($row = mysqli_fetch_assoc($result)))
{
   
//...
}
?>

The former will cause your script to run until max_execution_time is reached.
up
-21
gilles dot falquet at unige dot ch
7 years ago
Be careful when using fetch_assoc instead of fetch_row. If two columns of the result have the same column name, even if they are prefixed with different table names in the query, only one of them will be retained in the result. This is because the prefix is dropped (either by mysql or by this function)

For example if the query is

     select p1.name, p2.name
     from person p1, friend, person p2
     where p1.id = friend.person1 and p2.id = friend.person2

the arrays returned by fetch_assoc will be of the form

{'name' => 'bob'}
{'name' => 'anna'}

and not (as expected)

{'p1.name' => 'bob', 'p2.name' => 'alice'}
{'p1.name' => 'anna', 'p2.name' => 'irla'}
up
-32
Hesham Mohamed Sediek
9 years ago
when you fetch the data from the query variable
and try to fetch it again in another part of the script
from the same query variable ,
when you try to echo all data you have fetched,
it will not echo the data you have used in the first fetch
(it will exceed the results you have used in the first fetch).......

Example :
<?php
$connect
= new mysqli("localhost","root","root","elshamy")
or die (
mysqli_error());

$query=$connect->query("SELECT * FROM users ORDER BY id ASC");

$first_fetch=$query->fetch_array(MYSQLI_ASSOC);
echo
$first_fetch['id']."===>".$first_fetch['user_name']."\n--------------------\n";

while(
$row=$query->fetch_array(MYSQLI_ASSOC)){

/*it will exceed the first
id&user_name value that
you have use in the first fetch*/

echo $row['id']."  ".$row['user_name']."<br/>";
}
?>

above example will echo :
1===>userA
------------------------
2===>userB
3===>userC
4===>userD
up
-25
paul dot allsopp at inseego dot com
7 years ago
The official example given here breaks a cardinal rule, and should be rectified.

while ($row = $result->fetch_assoc())...

...breaks the rule of "assignment in condition".

while (($x = $y->getZ()) !== false) or
while (($x = $y->getZ()) !== null)

...is the correct syntax.

Conditional statements should always check for a boolean
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