Note that "if (! $sxe) {" may give you a false-negative if the XML document was empty (e.g. "<root />"). In that case, $sxe will be:
object(SimpleXMLElement)#1 (0) {
}
which will evaluate to false, even though nothing technically went wrong.
Consider instead: "if ($sxe === false) {"
Tratar con los errores XML
Tratar con los errores XML cuando se cargan documentos es una tarea muy sencilla. Utilizando la funcionalidad de libxml es posible suprimir todos los errores XML cuando se carga un documento para luego recorrerlos.
El objeto libXMLError, retornado por libxml_get_errors(), contiene varias propiedades, incluyendo el mensaje, línea y columna (posición) del error.
Ejemplo #1 Cargar un string XML erróneo
<?php
libxml_use_internal_errors(true);
$sxe = simplexml_load_string("<?xml version='1.0'><roto><xml></roto>");
if ($sxe === false) {
echo "Error cargando XML\n";
foreach(libxml_get_errors() as $error) {
echo "\t", $error->message;
}
}
?>El resultado del ejemplo sería:
Error cargando XML
Blank needed here
parsing XML declaration: '?>' expected
Opening and ending tag mismatch: xml line 1 and broken
Premature end of data in tag broken line 1
add a note
User Contributed Notes 4 notes
openbip at gmail dot com ¶
14 years ago
1337 at netapp dot com ¶
9 years ago
If you need to process the content of your broken XML-doc you might find this interesting. It has blown past a few simple corruptions for me.
http://php.net/manual/en/class.domdocument.php#domdocument.props.recover
tuxedobob ¶
10 years ago
Now that the /e modifier is considered deprecated in preg_replace, you can use a negative lookahead to replace unescaped ampersands with & without throwing warnings:
$str = preg_replace('/&(?!;{6})/', '&', $str);
You probably should have been doing this before /e was deprecated, actually.
Jacob Tabak ¶
14 years ago
If you are trying to load an XML string with some escaped and some unescaped ampersands, you can pre-parse the string to ecsape the unescaped ampersands without modifying the already escaped ones:
<?php
$s = preg_replace('/&[^; ]{0,6}.?/e', "((substr('\\0',-1) == ';') ? '\\0' : '&'.substr('\\0',1))", $s);
?>
