Is there a difference between casting to an array and using this function?
For instance, if we have:
$arrayObject = new ArrayObject([1, 2, 3]);
Is there a difference between these:
$array = (array) $arrayObject;
vs
$array = $arrayObject->getArrayCopy();
If not, is there any scenario where they would produce different results, or do they produce the result in different ways?
ArrayObject::getArrayCopy
(PHP 5, PHP 7, PHP 8)
ArrayObject::getArrayCopy — Crée une copie de l'objet ArrayObject
Liste de paramètres
Cette fonction ne contient aucun paramètre.
Valeurs de retour
Retourne une copie du tableau. Lorsque l'objet ArrayObject est un objet, le tableau retourné contient les propriétés de cet objet.
Exemples
Exemple #1 Exemple avec ArrayObject::getArrayCopy()
<?php
// Liste de fruits
$fruits = array("citrons" => 1, "oranges" => 4, "bananes" => 5, "pommes" => 10);
$fruitsArrayObject = new ArrayObject($fruits);
$fruitsArrayObject['poires'] = 4;
// Crée un copie des tableaux
$copy = $fruitsArrayObject->getArrayCopy();
print_r($copy);
?>L'exemple ci-dessus va afficher :
Array
(
[citrons] => 1
[oranges] => 4
[bananes] => 5
[pommes] => 10
[poires] => 4
)
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User Contributed Notes 5 notes
jlshor at buffalo dot edu ¶
7 years ago
Ivo von Putzer ¶
12 years ago
If you did something like this to make your constructor multidimensional capable you will have some trouble using getArrayCopy to get a plain array straight out of the method:
<?php
public function __construct( $array = array(), $flags = 2 )
{
// let’s give the objects the right and not the inherited name
$class = get_class($this);
foreach($array as $offset => $value)
$this->offsetSet($offset, is_array($value) ? new $class($value) : $value);
$this->setFlags($flags);
}
?>
That’s the way I solved it:
<?php
public function getArray($recursion = false)
{
// just in case the object might be multidimensional
if ( $this === true)
return $this->getArrayCopy();
return array_map( function($item){
return is_object($item) ? $item->getArray(true) : $item;
}, $this->getArrayCopy() );
}
?>
Hope this was useful!
spidgorny at gmail dot com ¶
7 years ago
<?php
$data = $likeArray->getArrayCopy();
?>
will NOT be magically called if you cast to array. Although I've expected it.
<?php
$nothing = (array)$likeArray;
?>
Here, $data != $nothing.
sorcerer ¶
7 years ago
When I used print_r ($fruitsArrayObject) instead of print_r ($copy), i.e. ignoring the getArrayCopy() step, I still got the same output. Why?
php at webflips dot net ¶
10 years ago
"When the ArrayObject refers to an object an array of the public properties of that object will be returned."
This description does not seem to be right:
<?php
class A
{
public $var = 'var';
protected $foo = 'foo';
private $bar = 'bar';
}
$o = new ArrayObject(new A());
var_dump($o->getArrayCopy());
/*
Dumps:
array(3) {
["var"]=>
string(3) "var"
["*foo"]=>
string(3) "foo"
["Abar"]=>
string(3) "bar"
}
*/
?>
So it does not only include the public properties.
