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mysqli::query

mysqli_query

(PHP 5, PHP 7, PHP 8)

mysqli::query -- mysqli_query — Exécute une requête sur la base de données

Description

Style orienté objet

public mysqli::query(string $query, int $result_mode = MYSQLI_STORE_RESULT): mysqli_result|bool

Style procédural

mysqli_query(mysqli $mysql, string $query, int $result_mode = MYSQLI_STORE_RESULT): mysqli_result|bool

Exécute une requête sur la base de données.

Avertissement

Avertissement de Sécurité : injection SQL

Si la requête contiens des variables d'entrées alors des déclarations préparées paramétrisées devrait être utilisé à la place. Alternativement, les données doivent être correctement formatées et toutes les chaînes de caractères doivent être échappées en utilisant la fonction mysqli_real_escape_string().

Pour les requêtes non-DML (qui n'est pas un INSERT, un UPDATE ou un DELETE), cette fonction est similaire à appeler mysqli_real_query() suivie de mysqli_use_result() ou mysqli_store_result().

Note:
Si vous passez une requête à mysqli_query() qui est plus longue que max_allowed_packet, les codes d'erreur en retour seront différents selon si vous utilisez MySQL Native Driver (mysqlnd) ou la MySQL Client Library (libmysqlclient). Le comportement est défini comme suit:

mysqlnd sur Linux retourne un code d'erreur de 1153. Le message d'erreur sera got a packet bigger than max_allowed_packet bytes.

mysqlnd sur Windows retourne un code d'erreur de 2006. Le message sera du type server has gone away.

libmysqlclient sur toute plateforme retourne le code d'erreur 2006. Le message sera du type server has gone away.

Liste de paramètres

mysql

Seulement en style procédural : Un objet mysqli retourné par la fonction mysqli_connect() ou mysqli_init().

query

La requête, sous la forme d'une chaîne de caractères.

result_mode

Le mode de résultat peut être l'une des 3 constantes indiquant comment le résultat sera retourné par le serveur MySQL.

MYSQLI_STORE_RESULT (par défaut) - renvoie un objet mysqli_result avec un ensemble de résultats mis en mémoire tampon.

MYSQLI_USE_RESULT - renvoie un objet mysqli_result avec un ensemble de résultats non tamponnés. Tant qu'il y a des enregistrements en attente d'être récupérés, la ligne de connexion sera occupée et tous les appels suivants renverront l'erreur Commands out of sync. Pour éviter l'erreur, tous les enregistrements doivent être récupérés du serveur ou l'ensemble de résultats doit être écarté en appelant la mysqli_free_result().

MYSQLI_ASYNC (disponible avec mysqlnd) - la requête est exécutée de manière asynchrone et aucun ensemble de résultats n'est immédiatement renvoyé. mysqli_poll() est alors utilisée pour obtenir les résultats de telles requêtes. Utilisée en combinaison avec la constante MYSQLI_STORE_RESULT ou MYSQLI_USE_RESULT.

Valeurs de retour

Retourne false en cas d'échec. Pour des requêtes réussites qui produisent un jeu de résultat tel que SELECT, SHOW, DESCRIBE ou EXPLAIN, mysqli_query() retournera un objet mysqli_result. Pour les autres types de requêtes ayant réussi, mysqli_query() retournera true.

Erreurs / Exceptions

Si le rapport d'erreurs mysqli est activé (MYSQLI_REPORT_ERROR) et que l'opération demandée échoue, un avertissement est généré. Si, en plus, le mode est défini sur MYSQLI_REPORT_STRICT, une mysqli_sql_exception est lancée à la place.

Exemples

Exemple #1 Exemple avec mysqli::query()

Style orienté objet

<?php

mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$mysqli = new mysqli("localhost", "my_user", "my_password", "world");

/* "Create table" ne retournera aucun jeu de résultats */
$mysqli->query("CREATE TEMPORARY TABLE myCity LIKE City");
printf("Table myCity créée avec succès.\n");

/* Requête "Select" retourne un jeu de résultats */
$result = $mysqli->query("SELECT Name FROM City LIMIT 10");
printf("Select a retourné %d lignes.\n", $result->num_rows);

/* Si nous avons à récupérer beaucoup de données, nous utilisons MYSQLI_USE_RESULT */
$result = $mysqli->query("SELECT * FROM City", MYSQLI_USE_RESULT);

/* Notez que nous ne pouvons exécuter aucune fonction qui agit sur le serveur tant que
    le jeu de résultats n'est pas clos. Tous les appels retourneront un 'out of sync' */
$mysqli->query("SET @a:='this will not work'");

Style procédural

<?php

mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$link = mysqli_connect("localhost", "my_user", "my_password", "world");

/* "Create table" ne retournera aucun jeu de résultats */
mysqli_query($link, "CREATE TEMPORARY TABLE myCity LIKE City");
printf("Table myCity créée avec succès.\n");

/* Requête "Select" retourne un jeu de résultats */
$result = mysqli_query($link, "SELECT Name FROM City LIMIT 10");
printf("Select a retourné %d lignes.\n", mysqli_num_rows($result));

/* Si nous avons à récupérer beaucoup de données, nous utilisons MYSQLI_USE_RESULT */
$result = mysqli_query($link, "SELECT * FROM City", MYSQLI_USE_RESULT);

/* Notez que nous ne pouvons exécuter aucune fonction qui agit sur le serveur tant que
    le jeu de résultats n'est pas clos. Tous les appels retourneront un 'out of sync' */
mysqli_query($link, "SET @a:='this will not work'");

Les exemples ci-dessus vont afficher :

Table myCity créée avec succès.
Select a retourné 10 lignes.
Fatal error: Uncaught mysqli_sql_exception: Commands out of sync; you can't run this command now in...

Voir aussi

mysqli_execute_query() - Prepares, binds parameters, and executes SQL statement
mysqli_real_query() - Exécute une requête SQL
mysqli_multi_query() - Exécute une ou plusieurs requêtes sur la base de donnée
mysqli_prepare() - Prépare une requête SQL pour l'exécution
mysqli_free_result() - Libère la mémoire associée à un résultat

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User Contributed Notes 21 notes

down

NUNTIUS ¶

16 years ago


This may or may not be obvious to people but perhaps it will help someone.



When running joins in SQL you may encounter a problem if you are trying to pull two columns with the same name. mysqli returns the last in the query when called by name. So to get what you need you can use an alias.



Below I am trying to join a user id with a user role. in the first table (tbl_usr), role is a number and in the second is a  text name (tbl_memrole is a lookup table). If I call them both as role I get the text as it is the last "role" in the query. If I use an alias then I get both as desired as shown below.



<?php

$sql = "SELECT a.uid, a.role AS roleid, b.role, 

            FROM tbl_usr a

            INNER JOIN tbl_memrole b

            ON a.role = b.id

            ";



    if ($result = $mysqli->query($sql)) {

        while($obj = $result->fetch_object()){

            $line.=$obj->uid;

            $line.=$obj->role;

            $line.=$obj->roleid;

        }

    }

    $result->close();

    unset($obj);

    unset($sql);

    unset($query);

    

?>

In this situation I guess I could have just renamed the role column in the first table roleid and that would have taken care of it, but it was a learning experience.

down

theyranos at gmail dot com ¶

13 years ago


The cryptic "Couldn't fetch mysqli" error message can mean any number of things, including:

1. You're trying to use a database object that you've already closed (as noted by ceo at l-i-e dot com). Reopen your database connection, or find the call to <?php mysqli_close($db); ?> or <?php $db->close(); ?> and remove it.
2. Your MySQLi object has been serialized and unserialized for some reason. Define a wakeup function to re-create your database connection. http://php.net/__wakeup 
3. Something besides you closed your mysqli connection (in particular, see http://bugs.php.net/bug.php?id=33772)
4. You mixed OOP and functional calls to the database object. (So, you have <?php $db->query() ?> in the same program as <?php mysqli_query($db) ?>).

down

petrus.jvr ¶

13 years ago


When calling multiple stored procedures, you can run into the following error: "Commands out of sync; you can't run this command now".
This can happen even when using the close() function on the result object between calls. 
To fix the problem, remember to call the next_result() function on the mysqli object after each stored procedure call. See example below:

<?php
// New Connection
$db = new mysqli('localhost','user','pass','database');

// Check for errors
if(mysqli_connect_errno()){
 echo mysqli_connect_error();
}

// 1st Query
$result = $db->query("call getUsers()");
if($result){
     // Cycle through results
    while ($row = $result->fetch_object()){
        $user_arr[] = $row;
    }
    // Free result set
    $result->close();
    $db->next_result();
}

// 2nd Query
$result = $db->query("call getGroups()");
if($result){
     // Cycle through results
    while ($row = $result->fetch_object()){
        $group_arr[] = $row;
    }
     // Free result set
     $result->close();
     $db->next_result();
}
else echo($db->error);

// Close connection
$db->close();
?>

down

xa at sagexa dot com ¶

2 years ago


"In PHP 8.1, the default error handling behavior of the MySQLi extension has changed from silencing errors to throw an Exception on errors. "
This is true even for the procedural use of mysqli, i.e. mysqli_query.
Hence, using if(!mysqli_query($c, $sql)) [...] is pointless.
To disable Exception throwing : mysqli_report(MYSQLI_REPORT_OFF);

down

Anonymous ¶

6 years ago


Here is an example of a clean query into a html table

<table>
   <tr>
     <th>First Name</th>
     <th>Last Name</th>
     <th>City</th>
   </tr>
   <?php while ($row = $myquery->fetch_assoc()) { ?>
   <tr>
     <td><?php echo $row["firstname"]; ?></td>
     <td><?php echo $row["lastname"]; ?></td>
     <td><?php echo $row["city"];?></td>
   </tr>
   <?php } ?>
 </table>

down

-2

registrations at jdfoxmicro dot com ¶

14 years ago


I like to save the query itself in a log file, so that I don't have to worry about whether the site is live.



For example, I might have a global function:



<?php

function UpdateLog ( $string , $logfile )  {

   $fh = fopen ( $logfile , 'a' );

   $fwrite ( $fh , strftime ('%F %T %z')." ".$string."\n";

   fclose ( $fh );

}

?>



Then in my mysql function error trapper, something like this:



<?php

   $error_msg = "Database error in [page].php / ";

   $error_msg .= mysqli_error ( $link )." / ";

   $error_msg .= $query;

   UpdateLog ( $error_msg , DB_ERROR_LOG_FILE );

?>



I also include the remote IP, user agent, etc., but I left it out of these code samples.  And have it e-mail me when an error is caught, too.



Jeff

down

-2

ceo at l-i-e dot com ¶

16 years ago


Translation:
"Couldn't fetch mysqli"

You closed your connection and are trying to use it again.

It has taken me DAYS to figure out what this obscure error message means...

down

-2

Beeners ¶

18 years ago


Stored Procedures.

Use mysqli_query to call a stored procedure that returns a result set. 

Here is a short example:

<?php
$mysqli = new mysqli(DBURI,DBUSER,DBPASS,DBNAME);
if (mysqli_connect_errno()) 
{
  printf("Connection failed: %s\n", mysqli_connect_error());
  exit();
}

$SQL = "CALL my_procedure($something)";
if ( ($result = $mysqli->query($SQL))===false )
{
  printf("Invalid query: %s\nWhole query: %s\n", $mysqli->error, $SQL);
  exit();
}

while ($myrow = $result->fetch_array(MYSQLI_ASSOC))
{
  $aValue[]=$myrow["a"];
  $bValue[]=$myrow["b"];
}
$result->close();
$mysqli->close();
?>
I hope this saves someone some time.

down

-11

info at ff dot net ¶

18 years ago


Calling Stored Procedures

Beeners' note/example will not work. Use mysqli_multi_query() to call a Stored Procedure. SP's have a second result-set which contains the status: 'OK' or 'ERR'. Using mysqli_query will not work, as there are multiple results.

<?php
$sQuery="CALL SomeSP('params')";
if(!mysqli_multi_query($sqlLink,$sQuery)) {
  // your error handler 
}
$sqlResult=mysqli_store_result($sqlLink);

if(mysqli_more_results($this->sqlLink))//Catch 'OK'/'ERR'
  while(mysqli_next_result($this->sqlLink));
?>

You will have to rewrite/expand this a bit for more usability of course, but it's just an example.

down

-15

joseph_robert_martinez at yahoo dot com ¶

10 years ago


For those using with replication enabled on their servers,  add a mysqli_select_db() statement before any data modification queries.  MySQL replication does not handle statements with db.table the same and will not replicate to the slaves if a scheme is not selected before.

Found out after days of resetting master and slaves on another site http://www.linuxquestions.org/questions/linux-server-73/mysql-5-1-not-replicating-properly-with-slave-823296/

down

-13

hunreal at gmail dot com ¶

20 years ago


Use difference collation/character for connect, result.
You can set the collation before your query.

E.g. want to set the collation to utf8_general_ci 
you can send the query "SET NAMES 'utf8'" first

<?php
$mysqli=new mysqli('localhost', 'root', 'password', 'test');
$mysqli->query("SET NAMES 'utf8'");
$q=$mysqli->query("select * from test");
while($r=$q->fetch_assoc()) {
    print_r($r);
}
?>

There are many variables about character settings.
By running sql command, SHOW VARIABLES LIKE 'char%'; 
There are some variables control the character usage.

character_set_client
character_set_connection
character_set_database
character_set_results
character_set_server
character_set_system

Also SET NAMES can repalce with one or some settings like SET character_set_results='utf8';

down

-14

jcwebb at dicoe dot com ¶

17 years ago


When building apps, i like to see the whole statement when if fails.
<?php
$q="SELECT somecolumn FROM sometable"; //some instruction
$r=mysqli_query($DBlink,$q) or die(mysqli_error($DBlink)." Q=".$q);
?>
If theres an error (like my numerous typing mistakes) this shows the entire instruction.
Good for development (not so good on production servers - simply find and replace when finished: $r=mysqli_query($DBlink,$q); )

Hope it helps. Jon

down

-16

Igor ¶

15 years ago


mysqli::query() can only execute one SQL statement.

Use mysqli::multi_query() when you want to run multiple SQL statements within one query.

down

-17

thomas dekker ¶

14 years ago


Building inserts can be annoying. This helper function inserts an array into a table, using the key names as column names:

<?php
  private function store_array (&$data, $table, $mysqli)
  {
    $cols = implode(',', array_keys($data));
    foreach (array_values($data) as $value)
    {
      isset($vals) ? $vals .= ',' : $vals = '';
      $vals .= '\''.$this->mysql->real_escape_string($value).'\'';
    }
    $mysqli->real_query('INSERT INTO '.$table.' ('.$cols.') VALUES ('.$vals.')');
  }
?>

Adapt it to your specific needs.

down

-20

ahmed dot 3abdolah at gmail dot com ¶

10 years ago


Hi, i created function that add  a new table using array , i work with it on my projects ...
<?PHP
                   /* this function was learned from PHP.net */
function array_keys_exist(&$key,array &$array){
                $keys = split("\|",$key);
                foreach($keys as $key_s){
                    if(array_key_exists($key_s, $array)) return true;
                    }
                return false;
            }
/*and this is my function */
array_create_table(array &$array){
        if(is_array($array)){
           $key = "table|rows|values";    
        $info = "";
        if(array_keys_exist($key,$array)){
        if(is_array($array["rows"]) and is_array($array["values"]) ){
                                         
            if(count($array["rows"]) == count($array["values"])) { 
                        for($i=0; $i<=count($array["rows"]); $i++){
    $info = $info." ".$array["rows"][$i]." ".$array["values"][$i]." NOT NULL ";
            if($i < count($array["rows"])-1 ) $info = $info.","; 
                    }
    $query = "CREATE TABLE ".$this->private_tables_name.$array["table"]." ";
    $query .= "( id INT NOT NULL AUTO_INCREMENT PRIMARY KEY, ".$info." )";
                    return $query;    
                        }
                        }
                }else return "Error";
                    }
            }

/* the use is simple */
$database = new database(); // connection to database i used mysqli ... 
$array = array("table"=>"MRO", "rows"=>array("name","username") , "values" => array("VARCHAR (50) "," VARCHAR (50) ") );

$query = array_create_table($array); // convert and create the query ...
if($database->query($query)) echo "Work"; else echo "Error"; // result : work

?>

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-17

marcus at synchromedia dot co dot uk ¶

13 years ago


The exact type returned by a successful query is mysqli_result.

down

-20

popere dot noel at yahoo dot com ¶

11 years ago


or you could just extend the class...
 in my case i already had a wraper for the db so something like this was easy :

 public function  free($result) {
  
  $result->free_result();
 $this->link->next_result();
 }

just tried it and it works like a charm ;-)

down

-9

omidbahrami1990 at gmail dot com ¶

6 years ago


This Is A Secure Way To Use mysqli::query
--------------------------------------------------------
<?php
function secured_query($sql)
{
$connection = new mysqli($host,$username,$password,$name);
    
if ($connection->connect_error) 
die("Secured");
    
$result=$connection->query($sql);
if($result==FALSE)
die("Secured");
    
$connection->close();        
return $result;    
}
/*
$host ---> DataBase IP Address
$username ---> DataBase Username
$password ---> DataBase Password
$name ---> DataBase Name
*/
?>

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-23

blinki bill, argodak at yahoo dot com ¶

11 years ago


Recently I had puzzling problem when performing DML queries, update in particular, each time a update query is called and then there are some more queries to follow this error will show on the page and go in the error_log:
"Fatal error:  Exception thrown without a stack frame in Unknown on line 0"

The strange thing is that all queries go through just fine so it didn't make much sense:

$update = mysqli_query($connection, $query_string);
if(!$update){
 echo 'Houston we have a problem '.mysqli_error($connection);
 exit;
}

In the above example "$update" is "true", mysqli_error() is empty and of course the update operation goes through, however the nasty super cryptic error appears on the page.
What makes even less sense to me is how I fixed it - just called "mysqli_free_result" after the update query and the problem was gone, however because mysqli_free_result is not supposed to be called after DML queries (to free what, a boolean? lol) it needs to be wrapped in a try catch block:

try{
 mysqli_free_result($update);
}catch (Exception $e){
 //do nothing
}

So, I don't know why but it seems that when DML queries are responsible for:
"Fatal error:  Exception thrown without a stack frame in Unknown on line 0"
calling "mysqli_free_result" after the query seems to be fixing the issue

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-6

David Marcus ¶

7 years ago


If you use the default resultmode of MYSQLI_STORE_RESULT, you can call $mysqli->close() right after $mysqli->query and before you use mysqli_result. This reduces the time the connection is open, which can help if the database server has a limit on how many connections there can be.

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-13

Anonymous ¶

7 years ago


I don't know is it bug or something , then first I write it here . Query SHOW with MYSQLI_USE_RESULT option don't show num_rows :
<?php
SHOW TABLES LIKE [some table], MYSQLI_USE_RESULT
num_rows // shows 0 !
?>

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