pg_fetch_result

(PHP 4 >= 4.2.0, PHP 5, PHP 7, PHP 8)

pg_fetch_result — Restituisce i valori da una risorsa di risultato

Descrizione

pg_fetch_result(resource $risultato, int $tupla, mixed $campo): mixed

pg_fetch_result() restituisce i valori da una risorsa risultato ottenuta mediante pg_query(). tupla è un intero. campo è il nome del campo (stringa) o l'indice del campo (intero). I parametri tupla e campo indicano quale cella nella tabella risultante va restituita. La numerazione delle tuple parte da 0. Invece di indicare il nome del campo, si può usare l'indice del campo sotto forma di numero senza virgolette. Gli indici dei campo partono da 0.

PostgreSQL ha molti tipi di dato e solo quelli più usati sono supportati direttamente da questa funzione. Tutti gli integer, sono restituiti come valori integer. Tutti i float, e i tipi real sono restituiti come valori float. Boolean è restituito come "t" o "f". Tutti gli altri tipi, compresi gli array, sono restituiti come stringhe formattate nello stesso modo di default che si puo vedere nel programma psql.

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User Contributed Notes 5 notes

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ElDiablo ¶

6 years ago


Please note that a very old bug (#76548) has been fixed in 7.2.8.

Previously, pg_fetch_result did not fetch the next row if $row was omitted.
It is now well the case, so bad use of the function can now cause some bugs in your codes.

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newby_AT_nobletec_DOT_com ¶

22 years ago


Comment on boolean fields:

If you retrieve a boolean value from the PostgreSQL database, be aware that the value returned will be either the character 't' or the character 'f', not an integer.  So, the statement

     if (pg_fetch_result($rsRecords,0,'blnTrueFalseField')) {
       echo "TRUE";
     } else {
       echo "FALSE";
     }

will echo "TRUE" in either case (True or False stored in the field).  In order to work as expected, do this instead:

     if (pg_fetch_result($rsRecords,0,'blnTrueFalseField') == 't') {
       echo "TRUE";
     } else {
       echo "FALSE";
     }

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Alan U. Kennington ¶

18 years ago


See bug #33809 http://bugs.php.net/bug.php?id=33809
Whether this really is a bug or a feature is not clear.
However, it is probably best to always put your column names in extra quotes.

$res = pg_query(...);
$colname = pg_field_name($res, $j);
pg_fetch_result($res, $i, "\"$colname\"");

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-2

Alan U Kennington ¶

18 years ago


In order to use upper case in pg_fetch_result column names, it is apparently necessary to include explicit quotation marks.

Thus when I do this sort of thing:

$res = pg_query(...);
$ncols = pg_num_fields($res);
for ($j = 0; $j < $ncols; ++$j) {
    $colname[$j] = pg_field_name($res, $j);
    $name = htmlspecialchars($colname[$j]);
    print("Column $j name = \"$name\"\n");
    $value = htmlspecialchars(pg_fetch_result($res, 0, $colname[$j]));
    print("Column \"{$colname[$j]}\" value = \"$value\"\n");
    }

I get this sort of thing:

[....]
Warning: pg_fetch_result() [function.pg-fetch-result]: Bad column offset specified in /.../view.php on line 247
Column 8 name = "VEC index"
Column "VEC index" value = ""

But if I change the $value line to this:

$value = htmlspecialchars(pg_fetch_result($res, 0, "\"$colname[$j]\""));

I get this:

[...]
Column 8 name = "VEC index"
Column "VEC index" value[0] = "47"

In my opinion, pg_fetch_result(...) should use the quotes already. In other words, this may be a bug in the PHP postgres library. It does not seem to be a documented feature of pg_fetch_result() although the postgresql manual documents it under "SQL syntax", "Lexical structure".

PHP version 5.1.4.
psql version 8.1.4.

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-3

Akbar ¶

20 years ago


Use can use pg_fetch_result when getting a value (like a smallint as in this example) returned by your stored procedure 

<?php
$pgConnection = pg_connect("dbname=users user=me");

$userNameToCheckFor = "metal";

$result = pg_query($pgConnection, "SELECT howManyUsersHaveThisName('$userNameToCheckFor')");

$count = pg_fetch_result($result, 0, 'howManyUsersHaveThisName');

?>

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