In versions prior to PHP 5.2.2 offsetExists() would return false if index value is null.
<?php
// running PHP 5.2.1
$params = new ArrayObject(array('INT'=>null, 'STR'=> null, 'BOOL'=>null, 'LOB'=>null));
$test = $params->offsetExists('INT');
var_dump($test);
// result would be bool(false)
// running PHP 5.2.2
$params = new ArrayObject(array('INT'=>null, 'STR'=> null, 'BOOL'=>null, 'LOB'=>null));
$test = $params->offsetExists('INT');
var_dump($test);
// result would be bool(true)
?>
Both tests where made on Windows platform.
ArrayObject::offsetExists
(PHP 5 >= 5.0.0, PHP 7)
ArrayObject::offsetExists — Returns whether the requested index exists
설명
인수
-
index -
The index being checked.
반환값
TRUE if the requested index exists, otherwise FALSE
예제
Example #1 ArrayObject::offsetExists() example
<?php
$arrayobj = new ArrayObject(array('zero', 'one', 'example'=>'e.g.'));
var_dump($arrayobj->offsetExists(1));
var_dump($arrayobj->offsetExists('example'));
var_dump($arrayobj->offsetExists('notfound'));
?>
위 예제의 출력:
bool(true) bool(true) bool(false)
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User Contributed Notes 1 note
goran at extensionsforjoomla dot com ¶
17 years ago
