Ds\Set::xor
(PECL ds >= 1.0.0)
Ds\Set::xor — Creates a new set using values in either the current instance or in another set, but not in both.
설명
public Ds\Set Ds\Set::xor
( Ds\Set
$set
)
Creates a new set containing values in the current instance as well as another set,
but not in both.
A ⊖ B = {x : x ∈ (A \ B) ∪ (B \ A)}
인수
-
set -
The other set.
반환값
A new set containing values in the current instance as well as another set,
but not in both.
예제
Example #1 Ds\Set::xor() example
<?php
$a = new \Ds\Set([1, 2, 3]);
$b = new \Ds\Set([3, 4, 5]);
var_dump($a->xor($b));
?>
위 예제의 출력 예시:
object(Ds\Set)#3 (4) {
[0]=>
int(1)
[1]=>
int(2)
[2]=>
int(4)
[3]=>
int(5)
}
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