is_subclass_of() works also with classes between the class of obj and the superclass.
example:
<?php
class A {};
class B extends A {};
class C extends B {};
$foo=new C();
echo ((is_subclass_of($foo,'A')) ? 'true' : 'false');
?>
echoes 'true' .
is_subclass_of
(PHP 4, PHP 5, PHP 7)
is_subclass_of — 이 클래스가 부모 클래스의 자식인지 확인
설명
주어진 object의 부모 중에
class_name 클래스가 존재하는지 확인합니다.
인수
-
object -
클래스명이나 객체 인스턴스
-
class_name -
클래스명
반환값
object가 class_name의 자식
클래스면 TRUE, 아니면 FALSE를 반환합니다.
변경점
| 버전 | 설명 |
|---|---|
| 5.0.3 |
object 인수를 문자열(클래스명)로 지정할 수
있습니다.
|
예제
Example #1 is_subclass_of() 예제
<?php
// 클래스 정의
class WidgetFactory
{
var $oink = 'moo';
}
// 자식 클래스 정의
class WidgetFactory_Child extends WidgetFactory
{
var $oink = 'oink';
}
// 새 객체 생성
$WF = new WidgetFactory();
$WFC = new WidgetFactory_Child();
if (is_subclass_of($WFC, 'WidgetFactory')) {
echo "yes, \$WFC is a subclass of WidgetFactory\n";
} else {
echo "no, \$WFC is not a subclass of WidgetFactory\n";
}
if (is_subclass_of($WF, 'WidgetFactory')) {
echo "yes, \$WF is a subclass of WidgetFactory\n";
} else {
echo "no, \$WF is not a subclass of WidgetFactory\n";
}
// PHP 5.3.0부터 사용 가능
if (is_subclass_of('WidgetFactory_Child', 'WidgetFactory')) {
echo "yes, WidgetFactory_Child is a subclass of WidgetFactory\n";
} else {
echo "no, WidgetFactory_Child is not a subclass of WidgetFactory\n";
}
?>
위 예제의 출력:
yes, $WFC is a subclass of WidgetFactory no, $WF is not a subclass of WidgetFactory yes, WidgetFactory_Child is a subclass of WidgetFactory
참고
- get_class() - 객체의 클래스명을 반환
- get_parent_class() - 객체나 클래스의 부모 클래스명을 얻습니다
- is_a() - 객체가 이 클래스나 부모 클래스 중 하나인지 확인
add a note
User Contributed Notes 8 notes
gunniboyh at web dot de ¶
18 years ago
nicholas at aquarionics dot com ¶
15 years ago
This might be useful to someone, so:
If you're using Autoload, you should be aware that this will attempt to autoload $classname if it isn't already loaded. I discovered this when I had something using is_subclass_of inside an error thrown by autoload, which then recursed until it ran out of memory.
alan at jynxy.net ¶
6 years ago
The $allow_string parameter is not very clearly documented. When true, it simply allows the first parameter to be the name of a class, instead of an object whose class we are interested in.
Some usage examples:
class parent_class {
// objects and methods ...
}
$possible_child_object = new possible_child_class(); // might be an extension of parent_class
$result = is_subclass_of($possible_child_object, 'parent_class'); // valid
$result = is_subclass_of($possible_child_object, 'parent_class', false); // valid
$result = is_subclass_of('possible_child_class', 'parent_class', true); // valid
$result = is_subclass_of('possible_child_class', 'parent_class', false); // not valid
Anonymous ¶
2 years ago
You can check if your current class is a child with:
<?php is_subclass_of($this, self::class) ?>
<?php
class a {
public function check(): bool {
return is_subclass_of($this, self::class);
}
}
class b extends a {}
$a = new a();
$b = new b();
echo $a->check() ? 'Yes' : 'No';
echo PHP_EOL;
echo $b->check() ? 'Yes' : 'No';
echo PHP_EOL;
?>
prints:
No
Yes
kostyl_kostyl gav-gav mail point ru ¶
15 years ago
<?php
interface I {
}
class A implements I {
}
class B extends A {
}
if (is_subclass_of('A', 'I')) {
echo 'good<br>';
}
else {
echo 'bad<br>';
}
if (is_subclass_of('B', 'I')) {
echo 'good<br>';
}
else {
echo 'bad<br>';
}
if (is_subclass_of('B', 'A')) {
echo 'good<br>';
}
else {
echo 'bad<br>';
}
?>
result:
bad <- you must to describe intermediate class B to be good
good
good
Damien Bezborodov ¶
15 years ago
If you need something similar to is_subclass_of() to determine if a class implements an interface before instantiating it, use reflection:
<?php
interface A_Interface {}
class A implements A_Interface {}
$reflectionA = new ReflectionClass('A');
var_dump(
$reflectionA->implementsInterface('A_Interface')
);
?>
bool(true)
jm ¶
16 years ago
It would appear that is_subclass_of is case insensitive unlike get_class in php5.
i.e.
<?php
class fooBar {}
class bar extends fooBar {}
assert(get_class(new fooBar()) == "fooBar");
assert(is_subclass_of(new bar(), "foobar") == true);
?>
i run across this while migrating some code from php4 to php5 and the code would only half-the-time break.
Ondra Zizka ¶
18 years ago
For PHP4:
<?php
/** Returns whether specified class is subclass of the other class. */
function is_subclass($sClass, $sExpectedParentClass){
do if( $sExpectedParentClass === $sClass ) return true;
while( false != ($sClass = get_parent_class($sClass)) );
return false;
}
// Test:
class A {} class B extends A {} class C extends B {} echo (int) is_subclass('C', 'A');
?>
