Are you sure you want to use JSON_NUMERIC_CHECK, really really sure?
Just watch this usecase:
<?php
// International phone number
json_encode(array('phone_number' => '+33123456789'), JSON_NUMERIC_CHECK);
?>
And then you get this JSON:
{"phone_number":33123456789}
Maybe it makes sense for PHP (as is_numeric('+33123456789') returns true), but really, casting it as an int?!
So be careful when using JSON_NUMERIC_CHECK, it may mess up with your data!
json_encode
(PHP 5 >= 5.2.0, PECL json >= 1.2.0, PHP 7)
json_encode — 값의 JSON 표현을 반환
인수
-
value -
인코드할
value. resource를 제외한 어떠한 자료형이라도 될 수 있습니다.이 함수는 UTF-8 인코드 데이터에만 작동합니다.
-
options -
PHP_JSON_HEX_QUOT,PHP_JSON_HEX_TAG,PHP_JSON_HEX_AMP,PHP_JSON_HEX_APOS로 조합하는 비트마스크. 기본값은 0.
반환값
성공시에 JSON 인코드 string를 반환합니다.
변경점
| 버전 | 설명 |
|---|---|
| 5.2.1 | JSON 인코드 기본 자료형 지원 추가 |
예제
Example #1 json_encode() 예제
<?php
$arr = array ('a'=>1,'b'=>2,'c'=>3,'d'=>4,'e'=>5);
echo json_encode($arr);
?>
위 예제의 출력:
{"a":1,"b":2,"c":3,"d":4,"e":5}
add a note
User Contributed Notes 9 notes
bohwaz ¶
12 years ago
elliseproduction at gmail dot com ¶
2 years ago
Notice that JSON_FORCE_OBJECT will convert all non-associative arrays to objects. This is not necessarily a good solution for empty arrays.
If you want to convert only empty arrays to objects, simply convert them to empty object before use json_encode function.
For example:
<?php
$foo=array(
'empty2object'=>(object)[],
'empty2array'=>[],
);
echo json_encode($foo); // {"empty2object":{},"empty2array":[]}
?>
Istratov Vadim ¶
15 years ago
Be careful with floating values in some locales (e.g. russian) with comma (",") as decimal point. Code:
<?php
setlocale(LC_ALL, 'ru_RU.utf8');
$arr = array('element' => 12.34);
echo json_encode( $arr );
?>
Output will be:
--------------
{"element":12,34}
--------------
Which is NOT a valid JSON markup. You should convert floating point variable to strings or set locale to something like "LC_NUMERIC, 'en_US.utf8'" before using json_encode.
ck at ergovia dot de ¶
11 years ago
Attention when passing a plain array to json_encode and using JSON_FORCE_OBJECT. It figured out that the index-order of the resulting JSON-string depends on the system PHP is running on.
$a = array("a" , "b", "c");
echo json_encode($a, JSON_FORCE_OBJECT);
On Xampp (Windows) you get:
{"0":"a","1":"b","2":"c"}';
On a machine running debian I get:
{"2":"a","1":"b","0":"c"}';
Note that the key:value pairs are different!
Solution here was to use array_combine to create a ssociative array and then pass it to json_encode:
json_encode(array_combine(range(0, count($a) - 1), $a), JSON_FORCE_OBJECT);
ryan at ryanparman dot com ¶
14 years ago
I came across the "bug" where running json_encode() over a SimpleXML object was ignoring the CDATA. I ran across http://bugs.php.net/42001 and http://bugs.php.net/41976, and while I agree with the poster that the documentation should clarify gotchas like this, I was able to figure out how to workaround it.
You need to convert the SimpleXML object back into an XML string, then re-import it back into SimpleXML using the LIBXML_NOCDATA option. Once you do this, then you can use json_encode() and still get back the CDATA.
<?php
// Pretend we already have a complex SimpleXML object stored in $xml
$json = json_encode(new SimpleXMLElement($xml->asXML(), LIBXML_NOCDATA));
?>
guilhenfsu at gmail dot com ¶
11 years ago
Solution for UTF-8 Special Chars.
<?
$array = array('nome'=>'Paição','cidade'=>'São Paulo');
$array = array_map('htmlentities',$array);
//encode
$json = html_entity_decode(json_encode($array));
//Output: {"nome":"Paição","cidade":"São Paulo"}
echo $json;
?>
Walter Tross ¶
9 years ago
If you need pretty-printed output, but want it indented by 2 spaces instead of 4:
$json_indented_by_4 = json_encode($output, JSON_UNESCAPED_SLASHES|JSON_PRETTY_PRINT);
$json_indented_by_2 = preg_replace('/^( +?)\\1(?=[^ ])/m', '$1', $json_indented_by_4);
Garrett ¶
16 years ago
A note about json_encode automatically quoting numbers:
It appears that the json_encode function pays attention to the data type of the value. Let me explain what we came across:
We have found that when retrieving data from our database, there are occasions when numbers appear as strings to json_encode which results in double quotes around the values.
This can lead to problems within javascript functions expecting the values to be numeric.
This was discovered when were were retrieving fields from the database which contained serialized arrays. After unserializing them and sending them through the json_encode function the numeric values in the original array were now being treated as strings and showing up with double quotes around them.
The fix: Prior to encoding the array, send it to a function which checks for numeric types and casts accordingly. Encoding from then on worked as expected.
Sam Barnum ¶
15 years ago
Note that if you try to encode an array containing non-utf values, you'll get null values in the resulting JSON string. You can batch-encode all the elements of an array with the array_map function:
<?php
$encodedArray = array_map(utf8_encode, $rawArray);
?>
