mysqli_result::$num_rows

mysqli_num_rows

(PHP 5, PHP 7)

mysqli_result::$num_rows -- mysqli_num_rowsGets the number of rows in a result

설명

객체 기반 형식

절차식 형식

int mysqli_num_rows ( mysqli_result $result )

Returns the number of rows in the result set.

The behaviour of mysqli_num_rows() depends on whether buffered or unbuffered result sets are being used. For unbuffered result sets, mysqli_num_rows() will not return the correct number of rows until all the rows in the result have been retrieved.

인수

result

순차 형식 전용: mysqli_query()mysqli_store_result()mysqli_use_result()가 반환한 결과셋 식별자.

반환값

Returns number of rows in the result set.

Note:

If the number of rows is greater than PHP_INT_MAX, the number will be returned as a string.

예제

Example #1 객체 기반 형식

<?php
$mysqli 
= new mysqli("localhost""my_user""my_password""world");

/* check connection */
if (mysqli_connect_errno()) {
    
printf("Connect failed: %s\n"mysqli_connect_error());
    exit();
}

if (
$result $mysqli->query("SELECT Code, Name FROM Country ORDER BY Name")) {

    
/* determine number of rows result set */
    
$row_cnt $result->num_rows;

    
printf("Result set has %d rows.\n"$row_cnt);

    
/* close result set */
    
$result->close();
}

/* close connection */
$mysqli->close();
?>

Example #2 절차식 형식

<?php
$link 
mysqli_connect("localhost""my_user""my_password""world");

/* check connection */
if (mysqli_connect_errno()) {
    
printf("Connect failed: %s\n"mysqli_connect_error());
    exit();
}

if (
$result mysqli_query($link"SELECT Code, Name FROM Country ORDER BY Name")) {

    
/* determine number of rows result set */
    
$row_cnt mysqli_num_rows($result);

    
printf("Result set has %d rows.\n"$row_cnt);

    
/* close result set */
    
mysqli_free_result($result);
}

/* close connection */
mysqli_close($link);
?>

위 예제들의 출력:

Result set has 239 rows.

참고

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User Contributed Notes 3 notes

up
123
borisigna
13 years ago
If you have problems making work this num_rows, you have to declare ->store_result() first.

<?php
$mysqli
= new mysqli("localhost","root", "", "tables");

$query = $mysqli->prepare("SELECT * FROM table1");
$query->execute();
$query->store_result();

$rows = $query->num_rows;

echo
$rows;

// Return 4 for example
?>
up
2
min0u
7 years ago
This function doesn't work with LIMIT used jointly with SQL_CALC_FOUND_ROWS. If you want to obtain the total rows found you must do it manually, example:

<?php
public function errorList(int $limit=25,int $offset=0){
       
$errorList = array();
       
$result = $this->con->query("SELECT SQL_CALC_FOUND_ROWS id, erreur FROM Erreurs ORDER BY id DESC LIMIT $limit OFFSET $offset");
        while(
$row = $result->fetch_assoc()){
           
$errorList[] = new Erreur($row);
        }
       
$result->free();
       
// $foundRows = $result->num_rows; // 25
       
$foundRows = $this->con->query("SELECT FOUND_ROWS() as foundRows");
       
$this->foundRows = $foundRows->fetch_assoc(); // 178
       
return $errorList;
}
?>
up
-30
justso at inbox dot ru
9 years ago
in php 5.3.8 had unexpected troubles when checking for mysqli_result::$num_rows
If the result of the query is empty then var_dump of the result will be like this:
class mysqli_result#5 (5) {
  public $current_field => NULL
  public $field_count => NULL
  public $lengths => NULL
  public $num_rows => NULL
  public $type => NULL
}
but var_dump($result->num_rows) will give integer-typed zero instead of NULL:
int(0)
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