Remember if you just want the days in the current month, use the date function:
$days = date("t");
cal_days_in_month
(PHP 4 >= 4.1.0, PHP 5, PHP 7)
cal_days_in_month — Return the number of days in a month for a given year and calendar
Descrierea
cal_days_in_month
( int
$calendar
, int $month
, int $year
) : int
This function will return the number of days in the
month of year for
the specified calendar.
Parametri
-
calendar -
Calendar to use for calculation
-
month -
Month in the selected calendar
-
year -
Year in the selected calendar
Valorile întoarse
The length in days of the selected month in the given calendar
Exemple
Example #1 cal_days_in_month() example
<?php
$number = cal_days_in_month(CAL_GREGORIAN, 8, 2003); // 31
echo "There were {$number} days in August 2003";
?>
add a note
User Contributed Notes 5 notes
brian at b5media dot com ¶
17 years ago
dbindel at austin dot rr dot com ¶
20 years ago
Here's a one-line function I just wrote to find the numbers of days in a month that doesn't depend on any other functions.
The reason I made this is because I just found out I forgot to compile PHP with support for calendars, and a class I'm writing for my website's open source section was broken. So rather than recompiling PHP (which I will get around to tomorrow I guess), I just wrote this function which should work just as well, and will always work without the requirement of PHP's calendar extension or any other PHP functions for that matter.
I learned the days of the month using the old knuckle & inbetween knuckle method, so that should explain the mod 7 part. :)
<?php
/*
* days_in_month($month, $year)
* Returns the number of days in a given month and year, taking into account leap years.
*
* $month: numeric month (integers 1-12)
* $year: numeric year (any integer)
*
* Prec: $month is an integer between 1 and 12, inclusive, and $year is an integer.
* Post: none
*/
// corrected by ben at sparkyb dot net
function days_in_month($month, $year)
{
// calculate number of days in a month
return $month == 2 ? ($year % 4 ? 28 : ($year % 100 ? 29 : ($year % 400 ? 28 : 29))) : (($month - 1) % 7 % 2 ? 30 : 31);
}
?>
Enjoy,
David Bindel
datlx at yahoo dot com ¶
2 years ago
function lastDayOfMonth(string $time, int $deltaMonth, string $format = 'Y-m-d')
{
try {
$year = date('Y', strtotime($time));
$month = date('m', strtotime($time));
$increaYear = floor(($deltaMonth + $month - 1) / 12);
$year += $increaYear;
$month = (($deltaMonth + $month) % 12) ?: 12;
$day = cal_days_in_month(CAL_GREGORIAN, $month, $year);
return $time . ' + ' . $deltaMonth . ' => ' . date($format, strtotime($year . '-' . $month . '-' . $day)) . "\n";
} catch (Exception $e) {
throw $e;
}
}
jeffbeall at comcast dot net ¶
20 years ago
This will work great in future dates but will give the wrong answer for dates before 1550 (approx) when leap year was introduced and the calendar lost a year or two.
Sorry now to be more specific it has been a while sine I had to account for those later dates and had to take that into account but just a heads up for others to watch out.
geko45pj at yahoo dot com ¶
17 years ago
<?php
# PHP Calendar (version 2.3), written by Keith Devens
function generate_calendar($year, $month, $days = array(), $day_name_length = 3, $month_href = NULL, $first_day = 0, $pn = array()){
$first_of_month = gmmktime(0,0,0,$month,1,$year);
#remember that mktime will automatically correct if invalid dates are entered
# for instance, mktime(0,0,0,12,32,1997) will be the date for Jan 1, 1998
# this provides a built in "rounding" feature to generate_calendar()
$day_names = array(); #generate all the day names according to the current locale
for($n=0,$t=(3+$first_day)*86400; $n<7; $n++,$t+=86400) #January 4, 1970 was a Sunday
$day_names[$n] = ucfirst(gmstrftime('%A',$t)); #%A means full textual day name
list($month, $year, $month_name, $weekday) = explode(',',gmstrftime('%m,%Y,%B,%w',$first_of_month));
$weekday = ($weekday + 7 - $first_day) % 7; #adjust for $first_day
$title = htmlentities(ucfirst($month_name)).' '.$year; #note that some locales don't capitalize month and day names
#Begin calendar. Uses a real <caption>. See http://diveintomark.org/archives/2002/07/03
@list($p, $pl) = each($pn); @list($n, $nl) = each($pn); #previous and next links, if applicable
if($p) $p = '<span class="calendar-prev">'.($pl ? '<a href="'.htmlspecialchars($pl).'">'.$p.'</a>' : $p).'</span> ';
if($n) $n = ' <span class="calendar-next">'.($nl ? '<a href="'.htmlspecialchars($nl).'">'.$n.'</a>' : $n).'</span>';
$calendar = '<table class="calendar">'."\n".
'<caption class="calendar-month">'.$p.($month_href ? '<a href="'.htmlspecialchars($month_href).'">'.$title.'</a>' : $title).$n."</caption>\n<tr>";
if($day_name_length){ #if the day names should be shown ($day_name_length > 0)
#if day_name_length is >3, the full name of the day will be printed
foreach($day_names as $d)
$calendar .= '<th abbr="'.htmlentities($d).'">'.htmlentities($day_name_length < 4 ? substr($d,0,$day_name_length) : $d).'</th>';
$calendar .= "</tr>\n<tr>";
}
if($weekday > 0) $calendar .= '<td colspan="'.$weekday.'"> </td>'; #initial 'empty' days
for($day=1,$days_in_month=gmdate('t',$first_of_month); $day<=$days_in_month; $day++,$weekday++){
if($weekday == 7){
$weekday = 0; #start a new week
$calendar .= "</tr>\n<tr>";
}
if(isset($days[$day]) and is_array($days[$day])){
@list($link, $classes, $content) = $days[$day];
if(is_null($content)) $content = $day;
$calendar .= '<td'.($classes ? ' class="'.htmlspecialchars($classes).'">' : '>').
($link ? '<a href="'.htmlspecialchars($link).'">'.$content.'</a>' : $content).'</td>';
}
else $calendar .= "<td>$day</td>";
}
if($weekday != 7) $calendar .= '<td colspan="'.(7-$weekday).'"> </td>'; #remaining "empty" days
return $calendar."</tr>\n</table>\n";
}
echo generate_calendar(2010, 12, 16,3,NULL,0,15, $first_of_month, $day_names, $day_names[$n]);
#echo generate_calendar($year, $month, $days,$day_name_length,$month_href,$first_day,$pn);
?>
