When working with FFI under a PHP ZTS environment, there is no standard way to change the directory with libraries (dll/so/dylib/etc), so to get around this problem, you should use something like this polyfill:
<?php
$directory = 'path/to/libraries';
switch (\PHP_OS_FAMILY) {
case 'Windows':
\FFI::cdef('extern unsigned char SetDllDirectoryA(const char* lpPathName);', 'kernel32.dll')
->SetDllDirectoryA($directory)
;
break;
case 'Linux':
case 'BSD':
\FFI::cdef('int setenv(const char *name, const char *value, int overwrite);')
->setenv('LD_LIBRARY_PATH', $directory, 1)
;
break;
case 'Darwin':
\FFI::cdef('int setenv(const char *name, const char *value, int overwrite);')
->setenv('DYLD_LIBRARY_PATH', $directory, 1)
;
break;
}
?>
chdir
(PHP 4, PHP 5, PHP 7)
chdir — Change directory
Descrierea
chdir
( string
$directory
) : bool
Changes PHP's current directory to
directory.
Parametri
-
directory -
The new current directory
Valorile întoarse
Întoarce valoarea true în cazul
succesului sau false în cazul eșecului.
Erori/Excepții
Throws an error of level E_WARNING on failure.
Exemple
Example #1 chdir() example
<?php
// current directory
echo getcwd() . "\n";
chdir('public_html');
// current directory
echo getcwd() . "\n";
?>
Exemplul de mai sus va afișa ceva similar cu:
/home/vincent /home/vincent/public_html
Note
Precauţie
If the PHP interpreter has been built with ZTS (Zend Thread Safety) enabled,
any changes to the current directory made through chdir()
will be invisible to the operating system. All built-in PHP functions will
still respect the change in current directory; but external library
functions called using FFI will not. You
can tell whether your copy of PHP was built with ZTS enabled using
php -i or the built-in constant
PHP_ZTS.
add a note
User Contributed Notes 3 notes
nesk at xakep dot ru ¶
4 years ago
php dot duke at qik dot nl ¶
15 years ago
When changing dir's under windows environments:
<?php
$path="c:\temp"';
chdir($path);
/* getcwd() gives you back "c:\temp" */
$path="c:\temp\"';
chdir($path);
/* getcwd() gives you back "c:\temp\" */
?>
to work around this inconsistency
doing a chdir('.') after the chdir always gives back "c:\temp"
herwin at snt dot utwente dot nl ¶
18 years ago
When using PHP safe mode and trying to change to a dir that is not accessible due to the safe mode restrictions, the function simply fails without generating any kind of error message.
(Tested in PHP 4.3.10-16, Debian Sarge default)
