<?php
// open in read-only mode
$db = dbase_open('/tmp/test.dbf', 0);
if ($db) {
$record_numbers = dbase_numrecords($db);
for ($i = 1; $i <= $record_numbers; $i++) {
// do something here, for each record
}
}
?>
Trying to get number of records in 1 of my "MySQL" tables. My database has 3 tables in it. How does it know which table to count records in.
Spent an hour and a half looking through Google links to dbase_numrecords, every place I go has a mirror image of the same example, but does not specify which table.
I understand, $db is the string that holds the name of the database. Or should it be the name of the table in the database.
dbase_numrecords
(PHP 5 < 5.3.0, dbase 5, dbase 7)
dbase_numrecords — Gets the number of records in a database
Descrierea
dbase_numrecords
( resource
$database
) : intGets the number of records (rows) in the specified database.
Notă:
Records which are marked as deleted are counted as well.
Notă:
Record numbers are between 1 and
dbase_numrecords($db), while field numbers are between 0 anddbase_numfields($db)-1.
Valorile întoarse
The number of records in the database, or false if an error occurs.
Istoricul schimbărilor
| Versiune | Descriere |
|---|---|
| dbase 7.0.0 |
database is now a resource
instead of an int.
|
Exemple
Example #1 Looping over all the records of the database
<?php
// open in read-only mode
$db = dbase_open('/tmp/test.dbf', 0);
if ($db) {
$record_numbers = dbase_numrecords($db);
for ($i = 1; $i <= $record_numbers; $i++) {
$record = dbase_get_record($db, $i);
if (!$record['deleted']) {
// do something with the $record
} else {
// do something with the deleted $record or ignore it
}
}
}
?>
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User Contributed Notes 1 note
Garry Cross ¶
17 years ago
