mysql_data_seek

(PHP 4, PHP 5)

mysql_data_seek — Move internal result pointer

Uyarı

Bu eklentinin kullanımı PHP 5.5.0 itibariyle önerilmemekte olup PHP 7.0.0'da kaldırılmıştır. Bu eklentinin yerine ya mysqli ya da PDO_MySQL eklentisi kullanılmalıdır. MySQL API seçerken MySQL API'ye Bakış belgesi yardımcı olabilir. Bu işlevin yerine kullanılabilecekler:

mysqli_data_seek()
PDO::FETCH_ORI_ABS

Açıklama

mysql_data_seek(resource $result, int $row_number): bool

mysql_data_seek() moves the internal row pointer of the MySQL result associated with the specified result identifier to point to the specified row number. The next call to a MySQL fetch function, such as mysql_fetch_assoc(), would return that row.

row_number starts at 0. The row_number should be a value in the range from 0 to mysql_num_rows() - 1. However if the result set is empty (mysql_num_rows() == 0), a seek to 0 will fail with an E_WARNING and mysql_data_seek() will return false.

Bağımsız Değişkenler

sonuç: resource türünde sorgu sonucu. Bu sonuç bir mysql_query() çağrısının sonucudur.
row_number: The desired row number of the new result pointer.

Dönen Değerler

Başarı durumunda true, başarısızlık durumunda false döner.

Örnekler

Örnek 1 mysql_data_seek() example

<?php
$link = mysql_connect('localhost', 'mysql_user', 'mysql_password');
if (!$link) {
    die('Could not connect: ' . mysql_error());
}
$db_selected = mysql_select_db('sample_db');
if (!$db_selected) {
    die('Could not select database: ' . mysql_error());
}
$query = 'SELECT last_name, first_name FROM friends';
$result = mysql_query($query);
if (!$result) {
    die('Query failed: ' . mysql_error());
}
/* fetch rows in reverse order */
for ($i = mysql_num_rows($result) - 1; $i >= 0; $i--) {
    if (!mysql_data_seek($result, $i)) {
        echo "Cannot seek to row $i: " . mysql_error() . "\n";
        continue;
    }

    if (!($row = mysql_fetch_assoc($result))) {
        continue;
    }

    echo $row['last_name'] . ' ' . $row['first_name'] . "<br />\n";
}

mysql_free_result($result);
?>

Notlar

Bilginize:
The function mysql_data_seek() can be used in conjunction only with mysql_query(), not with mysql_unbuffered_query().

Ayrıca Bakınız

mysql_query() - Send a MySQL query
mysql_num_rows() - Sonuçtaki satır sayısını al
mysql_fetch_row() - Get a result row as an enumerated array
mysql_fetch_assoc() - Fetch a result row as an associative array
mysql_fetch_array() - Fetch a result row as an associative array, a numeric array, or both
mysql_fetch_object() - Fetch a result row as an object

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User Contributed Notes 6 notes

down

kennethnash1134 at yahoo dot com ¶

20 years ago


/*here is a nice function for converting a mysql result row set into a 2d array, a time saver if need small data from several rows, saves you from having to do Alot of queries... would be nice to have this built into PHP future versions :) */

// simple example query
$r=mysql_query("select user,id,ip from accounts limit 10");

//starts the for loop, using mysql_num_rows() to count total
//amount of rows returned by $r
for($i=0; $i<mysql_num_rows($r); $i++){
             //advances the row in the mysql resource $r
    mysql_data_seek($r,$i);
             //assigns the array keys, $users[row][field]
    $users[$i]=mysql_fetch_row($r);
}

//simple, hope someone can use it :)
// -Kenneth Nash

down

saeed at photobookworldwide dot com ¶

12 years ago


Here, you can find the current pointer of selected row easily:



<?php

//selected row with id=4

$id    =    "4";



$result    =    mysql_query("select * from jos_components");



$num    =    mysql_num_rows($result);



for($i=0;$i<$num;$i++){

    

    mysql_data_seek($result,$i);

 

    $row    =    mysql_fetch_assoc($result);

    

    if($row['id']    ==    $id){

        

        $pointer    =    $i;

    }



 

}



// current pointer for selected row

echo $pointer;

?>

down

arturo_b at hotmail dot com ¶

19 years ago


hello, this script would be easy to understand for those that are novice in php whose want to understand about this function:

the table "user" have 2 columns "id" and "name".
"user" content:
position 0: "id"=195342481 "name"='Arthur'
position 1: "id"=179154675 "name"='John'
>>position 2<<: "id"=157761949 "name"='April' >>third row<<
position 3: "id"=124492684 "name"='Tammy'
position 4: "id"=191346457 "name"='Mike'

<?php
  mysql_connect("localhost", "root")
  mysql_select_db("test");
  $sql = mysql_query("select * from user");
  mysql_data_seek($sql, 2);
  echo "<table border=1>";
  while ($row = mysql_fetch_row($sql)){
    echo "<tr><td>$row[0]</td><td>$row[1]</td></tr>";
  }
  echo "</tabla>";
?>

explanation:
mysql_data_seek move internal result pointer to the third row of table user. Thus mysql_fetch_row will begin by april�s row.

down

-2

b.steinbrink at g m x dot de ¶

19 years ago


to kennethnash1134 at yahoo dot com

your loop can be done like this as well and i guess this is faster:

$r=mysql_query("select user,id,ip from accounts limit 10");

unset($users); // Just to be sure
while($users[] = mysql_fetch_row);
array_pop($users); // Drop the last entry which is FALSE

down

-4

Daniel ¶

16 years ago


Here is a simple function to "peek" at the position of the internal pointer in a query result:



<?php

function mysql_pointer_position($result_set) {

        $num_rows = mysql_num_rows($result_set);

        $i = 0;

        while($result = mysql_fetch_array($result_set)) {

            $i++;

        }

        $pointer_position = $num_rows - $i;



//Return pointer to original position

        if($pointer_position <= $num_rows - 1) {

            mysql_data_seek($result_set, $pointer_position);

        }

        return $pointer_position;

    }

?>

down

-5

Anonymous ¶

18 years ago


A helpful note about the 'resource' data type.

Since the 'resource' variable is pointing to a row in a result set at any given time, you can think of it as being passed to this function by reference every time you pass it or assign it to a variable.

<?

$sql = "SELECT * from <table>";
$result = mysql_query($sql);
$temp_result = $result;

while ($row = mysql_fetch_assoc($temp_result)) {
    // do stuff with $row
}

while ($row = mysql_fetch_assoc($result)) {
    // This code will never run because the 'resource' variable is pointing past the end of the result set,
    // even though it was *not* assigned by reference to $result2.
}

?>

Therefore, the following snipits are functionally identical:

<?

// Start snipit 1

$sql = "SELECT * from <table>";
$result = mysql_query($sql);

while ($row = mysql_fetch_assoc($result)) {
    // do stuff with $row
}

mysql_data_seek($result, 0);

while ($row = mysql_fetch_assoc($result)) {
    // do other stuff with $row
}

// Start snipit 2

$sql = "SELECT * from <table>";
$result = mysql_query($sql);
$temp_result = $result;

while ($row = mysql_fetch_assoc($temp_result)) {
    // do stuff with $row
}

mysql_data_seek($result, 0);

while ($row = mysql_fetch_assoc($temp_result)) {
    // do other stuff with $row
}

?>

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