I often like to have my results sent elsewhere in the format of an array (although keep in mind that if you just plan on traversing through the array in another part of the script, this extra step is just a waste of time).
This is my one-liner for transforming a mysqli_result set into an array.
<?php
$sql = new MySQLi($host, $username, $password, $database);
$result = $sql->query("SELECT * FROM `$table`;");
for ($set = array (); $row = $result->fetch_assoc(); $set[] = $row);
print_r($set);
?>
Outputs:
Array
(
[0] => Array
(
[id] => 1
[field2] => a
[field3] => b
),
[1] => Array
(
[id] => 2
[field2] => c
[field3] => d
)
)
I use other variations to adapt to the situation, i.e. if I am selecting only one field:
<?php
$sql = new MySQLi($host, $username, $password, $database);
$result = $sql->query("SELECT `field2` FROM `$table`;");
for ($set = array (); $row = $result->fetch_assoc(); $set[] = $row['field2']);
print_r($set);
?>
Outputs:
Array
(
[0] => a
[1] => c
)
Or, to make the array associative with the primary index (code assumes primary index is the first field in the table):
<?php
$sql = new MySQLi($host, $username, $password, $database);
$result = $sql->query("SELECT * FROM `$table`;");
for ($set = array (); $row = $result->fetch_assoc(); $set[array_shift($row)] = $row);
print_r($set);
?>
Outputs:
Array
(
[1] => Array
(
[field2] => a
[field3] => b
),
[2] => Array
(
[field2] => c
[field3] => d
)
)
mysqli_result::fetch_assoc
mysqli_fetch_assoc
(PHP 5, PHP 7, PHP 8)
mysqli_result::fetch_assoc -- mysqli_fetch_assoc — Fetch the next row of a result set as an associative array
Açıklama
Nesne yönelimli kullanım
Yordamsal kullanım
Fetches one row of data from the result set and returns it as an associative
array.
Each subsequent call to this function will return the next row within the
result set, or null if there are no more rows.
If two or more columns of the result have the same name, the last column will take precedence and overwrite any previous data. To access multiple columns with the same name, mysqli_fetch_row() may be used to fetch the numerically indexed array, or aliases may be used in the SQL query select list to give columns different names.
Bilginize: Bu işlevden dönen alan isimlerinin harf büyüklüklerinde değişiklik yapılmaz.
Bilginize: Bu işlev NULL alanlara PHP
nulldeğerini atar.
Bağımsız Değişkenler
-
sonuç -
Sadece yordamsal tarz: mysqli_query(), mysqli_store_result(), mysqli_use_result() veya mysqli_stmt_get_result() işlevinden dönen bir mysqli_result nesnesi.
Dönen Değerler
Returns an associative array representing the fetched row,
where each key in the array represents the name of one of the result
set's columns, null if there
are no more rows in the result set, başarısızlık durumunda false döner.
Örnekler
Örnek 1 mysqli_result::fetch_assoc() example
Nesne yönelimli kullanım
<?php
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$mysqli = new mysqli("localhost", "my_user", "my_password", "world");
$query = "SELECT Name, CountryCode FROM City ORDER BY ID DESC";
$result = $mysqli->query($query);
/* fetch associative array */
while ($row = $result->fetch_assoc()) {
printf("%s (%s)\n", $row["Name"], $row["CountryCode"]);
}Yordamsal kullanım
<?php
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$mysqli = mysqli_connect("localhost", "my_user", "my_password", "world");
$query = "SELECT Name, CountryCode FROM City ORDER BY ID DESC";
$result = mysqli_query($mysqli, $query);
/* fetch associative array */
while ($row = mysqli_fetch_assoc($result)) {
printf("%s (%s)\n", $row["Name"], $row["CountryCode"]);
}The above examples will output something similar to:
Pueblo (USA) Arvada (USA) Cape Coral (USA) Green Bay (USA) Santa Clara (USA)
Örnek 2 Comparison of mysqli_result iterator and mysqli_result::fetch_assoc() usage
mysqli_result can be iterated using foreach. The result set will always be iterated from the first row, regardless of the current position.
<?php
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$mysqli = new mysqli("localhost", "my_user", "my_password", "world");
$query = 'SELECT Name, CountryCode FROM City ORDER BY ID DESC';
// Using iterators
$result = $mysqli->query($query);
foreach ($result as $row) {
printf("%s (%s)\n", $row["Name"], $row["CountryCode"]);
}
echo "\n==================\n";
// Not using iterators
$result = $mysqli->query($query);
while ($row = $result->fetch_assoc()) {
printf("%s (%s)\n", $row["Name"], $row["CountryCode"]);
}Yukarıdaki örnek şuna benzer bir çıktı üretir:
Pueblo (USA) Arvada (USA) Cape Coral (USA) Green Bay (USA) Santa Clara (USA) ================== Pueblo (USA) Arvada (USA) Cape Coral (USA) Green Bay (USA) Santa Clara (USA)
Ayrıca Bakınız
- mysqli_fetch_array() - Fetch the next row of a result set as an associative, a numeric array, or both
- mysqli_fetch_column() - Fetch a single column from the next row of a result set
- mysqli_fetch_row() - Fetch the next row of a result set as an enumerated array
- mysqli_fetch_object() - Fetch the next row of a result set as an object
- mysqli_query() - Performs a query on the database
- mysqli_data_seek() - Adjusts the result pointer to an arbitrary row in the result
add a note
User Contributed Notes 6 notes
Miller ¶
11 years ago
Enrique Garcia ¶
1 year ago
There is a difference between MariaDB and MySQL(>5.4) whether the input parameter (mysqli object) has data or is empty (it comes from a previus query).
-MariaDB: you get an exception:
Fatal error: Uncaught TypeError: mysqli_fetch_assoc(): Argument #1 ($result) must be of type mysqli_result
-MySQL: you can continue, in spite of not having data in the mysqli object.
james dot phx at gmail dot com ¶
13 years ago
IMPORTANT NOTE:
If you were used to using code like this:
<?php
while(false !== ($row = mysql_fetch_assoc($result)))
{
//...
}
?>
You must change it to this for mysqli:
<?php
while(null !== ($row = mysqli_fetch_assoc($result)))
{
//...
}
?>
The former will cause your script to run until max_execution_time is reached.
gilles dot falquet at unige dot ch ¶
7 years ago
Be careful when using fetch_assoc instead of fetch_row. If two columns of the result have the same column name, even if they are prefixed with different table names in the query, only one of them will be retained in the result. This is because the prefix is dropped (either by mysql or by this function)
For example if the query is
select p1.name, p2.name
from person p1, friend, person p2
where p1.id = friend.person1 and p2.id = friend.person2
the arrays returned by fetch_assoc will be of the form
{'name' => 'bob'}
{'name' => 'anna'}
and not (as expected)
{'p1.name' => 'bob', 'p2.name' => 'alice'}
{'p1.name' => 'anna', 'p2.name' => 'irla'}
Hesham Mohamed Sediek ¶
9 years ago
when you fetch the data from the query variable
and try to fetch it again in another part of the script
from the same query variable ,
when you try to echo all data you have fetched,
it will not echo the data you have used in the first fetch
(it will exceed the results you have used in the first fetch).......
Example :
<?php
$connect = new mysqli("localhost","root","root","elshamy")
or die (mysqli_error());
$query=$connect->query("SELECT * FROM users ORDER BY id ASC");
$first_fetch=$query->fetch_array(MYSQLI_ASSOC);
echo $first_fetch['id']."===>".$first_fetch['user_name']."\n--------------------\n";
while($row=$query->fetch_array(MYSQLI_ASSOC)){
/*it will exceed the first
id&user_name value that
you have use in the first fetch*/
echo $row['id']." ".$row['user_name']."<br/>";
}
?>
above example will echo :
1===>userA
------------------------
2===>userB
3===>userC
4===>userD
paul dot allsopp at inseego dot com ¶
7 years ago
The official example given here breaks a cardinal rule, and should be rectified.
while ($row = $result->fetch_assoc())...
...breaks the rule of "assignment in condition".
while (($x = $y->getZ()) !== false) or
while (($x = $y->getZ()) !== null)
...is the correct syntax.
Conditional statements should always check for a boolean
