Note that this function really does what the description says, it returns the numeric user id of the user who *owns the file* containing the current script not the effective user id of user *running* the current script. Most applications will want the latter which is provided by posix_getuid().
getmyuid
(PHP 4, PHP 5, PHP 7, PHP 8)
getmyuid — 获取 PHP 脚本所有者的 UID
参数
此函数没有参数。
返回值
返回当前脚本的用户 ID，或在错误时返回 false。
参见
- getmygid() - 获取当前 PHP 脚本拥有者的 GID
- getmypid() - 获取 PHP 进程的 ID
- get_current_user() - 获取当前 PHP 脚本所有者名称
- getmyinode() - 获取当前脚本的索引节点（inode）
- getlastmod() - 获取页面最后修改的时间
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User Contributed Notes 2 notes
bozo_z_clown at yahoo dot com ¶
17 years ago
divinity76+spam at gmail dot com ¶
2 years ago
warning, at least 7.4-8.1 returns the owner of the initial entrypoint file rather the currently executing file,
meaning, if you have a.php owned by 1 containing
<?php var_dump(getmyuid());require_once("b.php"); ?>
and b.php owned by 2 containing
<?php var_dump(getmyuid());require_once("a.php"); ?>
running "php a.php" will get you int(1) int(1), and running "php b.php" will get you int(2) int(2), you won't get "int(1) int(2)"
