If you want to get the real name of the file without the directory name, you can just use the function basename() as the follow:
<?
$zip_dir = "./import/";
$zip = zip_open($zip_dir."import.zip");
if ($zip) {
while ($zip_entry = zip_read($zip)) {
$file = basename(zip_entry_name($zip_entry));
$fp = fopen($zip_dir.basename($file), "w+");
if (zip_entry_open($zip, $zip_entry, "r")) {
$buf = zip_entry_read($zip_entry, zip_entry_filesize($zip_entry));
zip_entry_close($zip_entry);
}
fwrite($fp, $buf);
fclose($fp);
echo "The file ".$file." was extracted to dir ".$zip_dir."\n<br>";
}
zip_close($zip);
}
?>
Thefore you can extract files without concern with the directory that is set inside the zip source.
Remember to give write permission (w) on that directory.
Hello from Brazil.
Leandro
zip_entry_name
(PHP 4 >= 4.1.0, PHP 5 >= 5.2.0, PHP 7, PHP 8, PECL zip >= 1.0.0)
zip_entry_name — 检索目录项的名称
警告
本函数已自 PHP 8.0.0 起被废弃。强烈建议不要依赖本函数。
返回值
目录项的名称， 或者在失败时返回 false。
add a note
User Contributed Notes 2 notes
leandro_dealmeida at hotmail dot com ¶
22 years ago
kevyn at opsone dot net ¶
16 years ago
Big note for filename with accents.
Some Zip softwares encode accents with CP850.
So use iconv for keeping your accents SAFE !
