We can do black magic, which is useful in templating block calls:
<?php
$object->__named('methodNameHere', array('arg3' => 'three', 'arg1' => 'one'));
...
/**
* Pass method arguments by name
*
* @param string $method
* @param array $args
* @return mixed
*/
public function __named($method, array $args = array())
{
$reflection = new ReflectionMethod($this, $method);
$pass = array();
foreach($reflection->getParameters() as $param)
{
/* @var $param ReflectionParameter */
if(isset($args[$param->getName()]))
{
$pass[] = $args[$param->getName()];
}
else
{
$pass[] = $param->getDefaultValue();
}
}
return $reflection->invokeArgs($this, $pass);
}
?>
ReflectionMethod::invokeArgs
(PHP 5 >= 5.1.2, PHP 7, PHP 8)
ReflectionMethod::invokeArgs — 带参数执行
返回值
返回方法返回值。
更新日志
| 版本 | 说明 |
|---|---|
| 8.0.0 |
args 的键现在将解释为参数的名称，而不是默默忽略。
|
示例
示例 #1 ReflectionMethod::invokeArgs() 示例
<?php
class HelloWorld {
public function sayHelloTo($name) {
return 'Hello ' . $name;
}
}
$reflectionMethod = new ReflectionMethod('HelloWorld', 'sayHelloTo');
echo $reflectionMethod->invokeArgs(new HelloWorld(), array('Mike'));
?>以上示例会输出：
Hello Mike
注释
注意:
如果函数有参数需为引用，那么它们必须以引用方式传入。
add a note
User Contributed Notes 4 notes
serg dot smertin at gmail dot com ¶
14 years ago
cweiske at cweiske dot de ¶
13 years ago
Passing arguments by reference works:
<?php $rm->invokeArgs($object, array(&$foo, $bar)); ?>
CodeCoutureXX at gmail dot com ¶
9 years ago
If you need to call ReflectionMethod::invokeArgs() on a static function you can pass NULL in for the $object parameter.
Example:
<?php
class myClass {
public static myStaticFunc($a, $b) {
return $a + $b;
}
}
$ref = new ReflectionMethod('myClass', 'myStaticFunc');
echo $ref->invokeArgs(NULL, [12, 7]);
?>
produces the following output:
19
agent_harris at secure-mail dot biz ¶
13 years ago
There is a simple workaround for the reference passing problem:
Since the reflection api has to handle all parameters in a generic way it has no chance to guess if you wish to pass data per value or reference.
But it seems that you can also decide to pass a reference from where you call the function or method (not just only by the ampersand prefix in its declaration).
So just do the following; which worked for me:
<?php
//...
$method->invoke($object, $inputValue, &$outputValue);
?>
Since this will only be necessary with arrays and primitive data types it should be acceptable in most cases to know in advance if you need to pass per reference. But it is probably although necessary to keep the ampersand always in the declaration (because of the at least two layers between the actual function and your invoke call).
If this is the expected behavior it will maybe make sense to mention it in the documentation for invoke and invokeArgs.
