mysqli_result::fetch_assoc

mysqli_fetch_assoc

(PHP 5, PHP 7, PHP 8)

mysqli_result::fetch_assoc -- mysqli_fetch_assocRécupère la ligne suivante d'un ensemble de résultats sous forme de tableau associatif

Description

Style orienté objet

public mysqli_result::fetch_assoc(): array|null|false

Style procédural

mysqli_fetch_assoc(mysqli_result $result): array|null|false

Retourne une ligne de données de l'ensemble de résultats et la renvoie sous forme de tableau associatif. Chaque appel ultérieur à cette fonction renverra la ligne suivante dans l'ensemble de résultats, ou null s'il n'y a plus de lignes.

Si deux ou plusieurs colonnes du résultat ont le même nom, la dernière colonne sera prioritaire et écrasera toutes les données précédentes. Pour accéder à plusieurs colonnes portant le même nom, la mysqli_fetch_row() peut être utilisée pour récupérer le tableau indexé numériquement ou des alias peuvent être utilisés dans la liste de sélection de la requête SQL pour donner des noms différents aux colonnes.

Note: Les noms des champs retournés par cette fonction sont sensibles à la casse.

Note: Cette fonction définit les champs NULL à la valeur PHP null.

Liste de paramètres

result

Style procédural uniquement : Un objet mysqli_result retourné par mysqli_query(), mysqli_store_result(), mysqli_use_result(), ou mysqli_stmt_get_result().

Valeurs de retour

Renvoie un tableau associatif représentant la ligne extraite, où chaque clé du tableau représente le nom d'une des colonnes du jeu de résultats, null s'il n'y a plus de lignes dans le jeu de résultats, ou false si une erreur survient.

Exemples

Exemple #1 Exemple mysqli_result::fetch_assoc()

Style orienté objet

<?php

mysqli_report
(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$mysqli = new mysqli("localhost", "my_user", "my_password", "world");

$query = "SELECT Name, CountryCode FROM City ORDER BY ID DESC";

$result = $mysqli->query($query);

/* fetch associative array */
while ($row = $result->fetch_assoc()) {
printf("%s (%s)\n", $row["Name"], $row["CountryCode"]);
}

Style procédural

<?php

mysqli_report
(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$mysqli = mysqli_connect("localhost", "my_user", "my_password", "world");

$query = "SELECT Name, CountryCode FROM City ORDER BY ID DESC";

$result = mysqli_query($mysqli, $query);

/* fetch associative array */
while ($row = mysqli_fetch_assoc($result)) {
printf("%s (%s)\n", $row["Name"], $row["CountryCode"]);
}

Les exemples ci-dessus vont afficher quelque chose de similaire à :

Pueblo (USA)
Arvada (USA)
Cape Coral (USA)
Green Bay (USA)
Santa Clara (USA)

Exemple #2 Comparaison de l'usage de mysqli_result iterator et mysqli_result::fetch_assoc()

mysqli_result peut être itéré en utilisant un foreach. Le jeu de résultats sera toujours itéré à partir de la première ligne, quel que soit la position actuelle.

<?php

mysqli_report
(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$mysqli = new mysqli("localhost", "my_user", "my_password", "world");

$query = 'SELECT Name, CountryCode FROM City ORDER BY ID DESC';

// Utilise un itérateur
$result = $mysqli->query($query);
foreach (
$result as $row) {
printf("%s (%s)\n", $row["Name"], $row["CountryCode"]);
}

echo
"\n==================\n";

// N'utilise pas d'itérateur
$result = $mysqli->query($query);
while (
$row = $result->fetch_assoc()) {
printf("%s (%s)\n", $row["Name"], $row["CountryCode"]);
}

Résultat de l'exemple ci-dessus est similaire à :

Pueblo (USA)
Arvada (USA)
Cape Coral (USA)
Green Bay (USA)
Santa Clara (USA)

==================
Pueblo (USA)
Arvada (USA)
Cape Coral (USA)
Green Bay (USA)
Santa Clara (USA)

Voir aussi

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User Contributed Notes 6 notes

up
86
Miller
11 years ago
I often like to have my results sent elsewhere in the format of an array (although keep in mind that if you just plan on traversing through the array in another part of the script, this extra step is just a waste of time).

This is my one-liner for transforming a mysqli_result set into an array.
<?php
$sql
= new MySQLi($host, $username, $password, $database);

$result = $sql->query("SELECT * FROM `$table`;");
for (
$set = array (); $row = $result->fetch_assoc(); $set[] = $row);
print_r($set);
?>

Outputs:
Array
(
    [0] => Array
        (
            [id] => 1
            [field2] => a
            [field3] => b
        ),
    [1] => Array
        (
            [id] => 2
            [field2] => c
            [field3] => d
        )
)

I use other variations to adapt to the situation, i.e. if I am selecting only one field:
<?php
$sql
= new MySQLi($host, $username, $password, $database);
$result = $sql->query("SELECT `field2` FROM `$table`;");
for (
$set = array (); $row = $result->fetch_assoc(); $set[] = $row['field2']);
print_r($set);
?>
Outputs:
Array
(
    [0] => a
    [1] => c
)

Or, to make the array associative with the primary index (code assumes primary index is the first field in the table):
<?php
$sql
= new MySQLi($host, $username, $password, $database);
$result = $sql->query("SELECT * FROM `$table`;");
for (
$set = array (); $row = $result->fetch_assoc(); $set[array_shift($row)] = $row);
print_r($set);
?>
Outputs:
Array
(
    [1] => Array
        (
            [field2] => a
            [field3] => b
        ),
    [2] => Array
        (
            [field2] => c
            [field3] => d
        )
)
up
2
Enrique Garcia
1 year ago
There is a difference between MariaDB and MySQL(>5.4) whether the input parameter (mysqli object) has data or is empty (it comes from a previus query).
-MariaDB:  you get an exception:
Fatal error: Uncaught TypeError: mysqli_fetch_assoc(): Argument #1 ($result) must be of type mysqli_result
-MySQL: you can continue, in spite of not having data in the mysqli object.
up
28
james dot phx at gmail dot com
13 years ago
IMPORTANT NOTE:

If you were used to using code like this:

<?php
while(false !== ($row = mysql_fetch_assoc($result)))
{
   
//...
}
?>

You must change it to this for mysqli:

<?php
while(null !== ($row = mysqli_fetch_assoc($result)))
{
   
//...
}
?>

The former will cause your script to run until max_execution_time is reached.
up
-21
gilles dot falquet at unige dot ch
7 years ago
Be careful when using fetch_assoc instead of fetch_row. If two columns of the result have the same column name, even if they are prefixed with different table names in the query, only one of them will be retained in the result. This is because the prefix is dropped (either by mysql or by this function)

For example if the query is

     select p1.name, p2.name
     from person p1, friend, person p2
     where p1.id = friend.person1 and p2.id = friend.person2

the arrays returned by fetch_assoc will be of the form

{'name' => 'bob'}
{'name' => 'anna'}

and not (as expected)

{'p1.name' => 'bob', 'p2.name' => 'alice'}
{'p1.name' => 'anna', 'p2.name' => 'irla'}
up
-32
Hesham Mohamed Sediek
9 years ago
when you fetch the data from the query variable
and try to fetch it again in another part of the script
from the same query variable ,
when you try to echo all data you have fetched,
it will not echo the data you have used in the first fetch
(it will exceed the results you have used in the first fetch).......

Example :
<?php
$connect
= new mysqli("localhost","root","root","elshamy")
or die (
mysqli_error());

$query=$connect->query("SELECT * FROM users ORDER BY id ASC");

$first_fetch=$query->fetch_array(MYSQLI_ASSOC);
echo
$first_fetch['id']."===>".$first_fetch['user_name']."\n--------------------\n";

while(
$row=$query->fetch_array(MYSQLI_ASSOC)){

/*it will exceed the first
id&user_name value that
you have use in the first fetch*/

echo $row['id']."  ".$row['user_name']."<br/>";
}
?>

above example will echo :
1===>userA
------------------------
2===>userB
3===>userC
4===>userD
up
-25
paul dot allsopp at inseego dot com
7 years ago
The official example given here breaks a cardinal rule, and should be rectified.

while ($row = $result->fetch_assoc())...

...breaks the rule of "assignment in condition".

while (($x = $y->getZ()) !== false) or
while (($x = $y->getZ()) !== null)

...is the correct syntax.

Conditional statements should always check for a boolean
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