It appears that the $offset value is a character count not a byte count. (This may seem obvious but it isn't explicitly stated)
(PHP 4 >= 4.0.6, PHP 5, PHP 7, PHP 8)
mb_strpos — Find position of first occurrence of string in a string
Finds position of the first occurrence of a string in a string.
Performs a multi-byte safe strpos() operation based on number of characters. The first character's position is 0, the second character position is 1, and so on.
haystack
The string being checked.
needle
The string to find in haystack
. In contrast
with strpos(), numeric values are not applied
as the ordinal value of a character.
offset
The search offset. If it is not specified, 0 is used. A negative offset counts from the end of the string.
encoding
Il parametro encoding
è la codifica dei caratteri. Se è omesso, verrà utilizzata la
codifica interna.
Returns the numeric position of
the first occurrence of needle
in the
haystack
string. If
needle
is not found, it returns false
.
Versione | Descrizione |
---|---|
8.0.0 |
needle now accepts an empty string.
|
8.0.0 |
encoding is nullable now.
|
7.1.0 |
Support for negative offset s has been added.
|
It appears that the $offset value is a character count not a byte count. (This may seem obvious but it isn't explicitly stated)
a sample mb_str_replace function:
function mb_str_replace($haystack, $search,$replace, $offset=0,$encoding='auto'){
$len_sch=mb_strlen($search,$encoding);
$len_rep=mb_strlen($replace,$encoding);
while (($offset=mb_strpos($haystack,$search,$offset,$encoding))!==false){
$haystack=mb_substr($haystack,0,$offset,$encoding)
.$replace
.mb_substr($haystack,$offset+$len_sch,1000,$encoding);
$offset=$offset+$len_rep;
if ($offset>mb_strlen($haystack,$encoding))break;
}
return $haystack;
}
sorry, my previous post had an error. replace the 1000 with strlen($haystack) to handle strings longer than 1000 chars.
btw. This is an issue with the mbstring functions. you can't specify the $encoding without specifying a $length, thus this reduces the functionality of mb_substr compared to substr