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    dbase_get_record_with_names

    (PHP 5 < 5.3.0, dbase 5, dbase 7)

    dbase_get_record_with_names — Gets a record from a database as an associative array

    説明

    dbase_get_record_with_names(resource $database, int $number): array

    Gets a record from a dBase database as an associative array.

    パラメータ

    database

    The database resource, returned by dbase_open() or dbase_create().

    number

    The index of the record between 1 and dbase_numrecords($dbase_identifier).

    戻り値

    An associative array with the record. This will also include a key named deleted which is set to 1 if the record has been marked for deletion (see dbase_delete_record()). Therefore it is not possible to retrieve the value of a field named deleted with this function.

    各フィールドは適切な PHP の型に変換されますが、以下に挙げる例外があります。

    • Date は文字列のままになります。
    • DateTime は文字列に変換されます。
    • PHP_INT_MIN..PHP_INT_MAX の範囲外の Integer は文字列になります。
    • dbase 7.0.0 より前のバージョンでは、boolean (L) が 1 あるいは 0 に変換されていました。

    On error, dbase_get_record_with_names() will return false.

    変更履歴

    バージョン 説明
    dbase 7.0.0 database is now a resource instead of an int.

    例

    例1 Listing all the registered members in the database

    <?php
    // open in read-only mode
    $db = dbase_open('/tmp/test.dbf', 0);

    if (    $db) {
    $record_numbers = dbase_numrecords($db);
    for (    $i = 1; $i <= $record_numbers; $i++) {
    $row = dbase_get_record_with_names($db, $i);
    if (    $row['ismember'] == 1) {
    echo     "Member #$i: " . trim($row['name']) . "\n";
    }
    }
    }
    ?>

    参考

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    User Contributed Notes 2 notes

    up
    2
    bishop
    19 years ago
    I would like to emphasize that record numbers begin with 1, not 0. So, this is wrong:
    <?php
    $recCnt     = dbase_numrecords($fh);
    for (    $recNum = 0; $recNum < $recCnt; $recNum++) {
            // wrong! first record will fail
            $record = dbase_get_record_with_names($fh, $recNum);
    }
    ?>

    This is right:

    <?php
    $recCnt     = dbase_numrecords($fh);
    for (    $recNum = 1; $recNum <= $recCnt; $recNum++) {
            // right! record #s begin with 1, don't forget <=
            $record = dbase_get_record_with_names($fh, $recNum);
    }
    ?>
    up
    -1
    Anonymous
    19 years ago
    $foo_db = dbase_open ( 'foo.dbf', 0);

    if ($foo_db) {
      $rn = dbase_numrecords($foo_db);

      echo "Record 0: ";
      $test = dbase_get_record_with_names($foo_db, 0);
      echo $test['deleted'] . " FOO BAR: '" . $test['BAR'] . "'\n";

      echo "Record n+1: ";
      $test = dbase_get_record_with_names($foo_db, $rn+1);
      echo $test['deleted'] . " FOO BAR: '" . $test['BAR'] . "'\n";

    }

    Gives:

    Record 0: 0 FOO BAR: ' '

    Record n+1:
    Warning: Tried to read bad record 30 in ./DisplayAccounts.php on line 21
    FOO BAR: ''

    0 is not an error record, it's just empty - and actually, not quite empty, as you see BAR got a single space.
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