dbase_numrecords

(PHP 5 < 5.3.0, dbase 5, dbase 7)

dbase_numrecords — Gets the number of records in a database

説明

dbase_numrecords(resource $database): int

Gets the number of records (rows) in the specified database.

注意:
Records which are marked as deleted are counted as well.

注意:
Record numbers are between 1 and dbase_numrecords($db), while field numbers are between 0 and dbase_numfields($db)-1.

パラメータ

database: The database resource, returned by dbase_open() or dbase_create().

戻り値

The number of records in the database, or false if an error occurs.

変更履歴

バージョン	説明
dbase 7.0.0	`database` is now a resource instead of an int.

例

例1 Looping over all the records of the database

<?php

// open in read-only mode
$db = dbase_open('/tmp/test.dbf', 0);

if ($db) {
  $record_numbers = dbase_numrecords($db);
  for ($i = 1; $i <= $record_numbers; $i++) {
      $record = dbase_get_record($db, $i);
      if (!$record['deleted']) {
          // do something with the $record
      } else {
          // do something with the deleted $record or ignore it
      }
  }
}

?>

参考

dbase_numfields() - Gets the number of fields of a database

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User Contributed Notes 1 note

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-5

Garry Cross ¶

16 years ago


<?php

// open in read-only mode
$db = dbase_open('/tmp/test.dbf', 0);

if ($db) {
  $record_numbers = dbase_numrecords($db);
  for ($i = 1; $i <= $record_numbers; $i++) {
      // do something here, for each record
  }
}

?>

Trying to get number of records in 1 of my "MySQL" tables. My database has 3 tables in it. How does it know which table to count records in.

Spent an hour and a half looking through Google links to dbase_numrecords, every place I go has a mirror image of the same example, but does not specify which table.

I understand, $db is the string that holds the name of the database. Or should it be the name of the table in the database.

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