<?php
// open in read-only mode
$db = dbase_open('/tmp/test.dbf', 0);
if ($db) {
$record_numbers = dbase_numrecords($db);
for ($i = 1; $i <= $record_numbers; $i++) {
// do something here, for each record
}
}
?>
Trying to get number of records in 1 of my "MySQL" tables. My database has 3 tables in it. How does it know which table to count records in.
Spent an hour and a half looking through Google links to dbase_numrecords, every place I go has a mirror image of the same example, but does not specify which table.
I understand, $db is the string that holds the name of the database. Or should it be the name of the table in the database.
dbase_numrecords
(PHP 5 < 5.3.0, dbase 5, dbase 7)
dbase_numrecords — Gets the number of records in a database
説明
Gets the number of records (rows) in the specified database.
注意:
Records which are marked as deleted are counted as well.
注意:
Record numbers are between 1 and
dbase_numrecords($db), while field numbers are between 0 anddbase_numfields($db)-1.
戻り値
The number of records in the database, or false if an error occurs.
例
例1 Looping over all the records of the database
<?php
// open in read-only mode
$db = dbase_open('/tmp/test.dbf', 0);
if ($db) {
$record_numbers = dbase_numrecords($db);
for ($i = 1; $i <= $record_numbers; $i++) {
$record = dbase_get_record($db, $i);
if (!$record['deleted']) {
// do something with the $record
} else {
// do something with the deleted $record or ignore it
}
}
}
?>
add a note
User Contributed Notes 1 note
Garry Cross ¶
17 years ago
