This function will convert "cn=bryan,ou=users,ou=admin,o=apachetoolbox" to "bryan,users,admin,apachetoolbox".
ldap_dn2ufn
(PHP 4, PHP 5, PHP 7)
ldap_dn2ufn — Convert DN to User Friendly Naming format
설명
string ldap_dn2ufn
( string
$dn
)
Turns the specified dn, into a more user-friendly
form, stripping off type names.
인수
-
dn -
The distinguished name of an LDAP entity.
반환값
Returns the user friendly name.
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User Contributed Notes 4 notes
bryan at apachetoolbox dot com ¶
23 years ago
naaina at gmail dot com ¶
19 years ago
Don't know if anyone is interested in this, but this is a modified and more dynamic version of the posting below. Since ldap_dn2ufn takes ',' as delimiter for the UFNs, we'll also use it here. $pHowToBuild specifies, how the DN is going to be build.
Short example:
$myUFN = ldap_dn2ufn("cn=naaina, ou=container1, ou=container2, ou=container3, o=private, c=de");
echo $myUFN . "\n"; // will return "naaina, container1, container2, container3, private, de"
$myDN = $ldapObject->conv_ufn2dn($myUFN);
echo $myDN . "\n"; // will return "cn=naaina,ou=container1,ou=container2,ou=container3,o=private,c=de"
For the object name, $pHowToBuild["object"] is going to be used as prefix - for containers $pHowToBuild["container"] and for the last n elements $pHowToBuild["last"].
<?php
function ldap_ufn2dn (
$pUFN,
$pDelimiter = ",",
$pHowToBuild = array(
"object" => "cn",
"container" => "ou",
"last" => array("o", "c")
)
)
{
$resultDN = null;
if(!empty($pUFN)) {
/* Check $pHowToBuild */
if(is_array($pHowToBuild)) {
/* Check if required keys are existent */
if(array_key_exists("object", $pHowToBuild) &&
array_key_exists("container", $pHowToBuild) &&
array_key_exists("last", $pHowToBuild))
{
$ufnArray = explode($pDelimiter, $pUFN);
$ufnLast = count($ufnArray) - count($pHowToBuild["last"]);
/* Remove empty values */
foreach($ufnArray as $objKey => $objVal)
if(empty($objVal))
array_splice($ufnArray, $objKey, 1);
/* Now build the DN ... */
foreach($ufnArray as $objKey => $objVal) {
$objVal = trim($objVal);
if($objKey == 0) {
/* For the object */
$resultDN .= $pHowToBuild["object"] . "=" . $objVal . ",";
} elseif ($objKey >= $ufnLast) {
/* For last parts of the DN */
$resultDN .= $pHowToBuild["last"][$objKey - $ufnLast] . "=" . $objVal;
if(($objKey - $ufnLast - 1) != 0) {
$resultDN .= ",";
}
} else {
/* For containers */
$resultDN .= $pHowToBuild["container"] . "=" . $objVal . ",";
}
}
}
}
}
return $resultDN;
}
?>
alex at netflex dot nl ¶
22 years ago
The function of bryan will only work if you start with an Organization and using only an Organizational Unit as a container and the object is an CN.
For example:
$DN = "CN=DNS,CN=Authorized Login Methods,CN=Security";
echo ($DN = ldap_dn2ufn($DN)) . "\n";
echo ($DN = ldap_ufn2dn($DN)) . "\n";
will echo:
DNS,Authorized Login Methods,Security
CN=DNS,OU=Authorized Login Methods,O=Security
bryan at apachetoolbox dot com ¶
23 years ago
function ldap_unf2dn($unf,$delimeter=".") {
$seperated = explode($delimeter,$unf); //split the unf up by the given delimeter
$LastKey=count($seperated)-1; //0 is the first key to total-1 would be the last key
foreach($seperated as $key => $value) {
if ($key == 1) { //first variable is the CN
$dn="${dn}cn=$value,";
} elseif ($key == $LastKey) { //last variable, so it's the O
$dn="${dn}o=$value";
} elseif ($value == "") { //value is blank, so continue
continue;
} else { //just a typical OU
$dn="${dn}ou=$value,";
}
};
return $dn;
}
$unf=".bryan.users.admin.apachetoolbox";
$dn=ldap_unf2dn($unf);
print "$dn" // will give me "cn=bryan,ou=users,ou=TS,o=apachetoolbox"
