배열 연산자

배열 연산자
예제 이름 결과
$a + $b Union $a와 $b의 합집합.
$a == $b Equality $a와 $b가 동일한 키/값 쌍을 가지면 TRUE.
$a === $b Identity $a와 $b가 동일한 키/값 쌍을 동일한 순서와 동일한 자료형으로 가지면 TRUE.
$a != $b Inequality $a가 $b와 같지 않으면 TRUE.
$a <> $b Inequality $a가 $b와 같지 않으면 TRUE.
$a !== $b Non-identity $a가 $b와 동일하지 않으면 TRUE.

+ 연산자는 오른쪽 배열에서 왼쪽 배열로 키를 유지하며 원소를 덧붙입니다. 중복되는 키를 덮어쓰지 않습니다.

<?php
$a 
= array("a" => "apple""b" => "banana");
$b = array("a" => "pear""b" => "strawberry""c" => "cherry");

$c $a $b// Union of $a and $b
echo "Union of \$a and \$b: \n";
var_dump($c);

$c $b $a// Union of $b and $a
echo "Union of \$b and \$a: \n";
var_dump($c);
?>
실행하면, 위 스크립트는 다음을 출력합니다:
Union of $a and $b:
array(3) {
  ["a"]=>
  string(5) "apple"
  ["b"]=>
  string(6) "banana"
  ["c"]=>
  string(6) "cherry"
}
Union of $b and $a:
array(3) {
  ["a"]=>
  string(4) "pear"
  ["b"]=>
  string(10) "strawberry"
  ["c"]=>
  string(6) "cherry"
}

동일한 키와 값을 가지고 있으면, 비교할 때 같은 배열 원소입니다.

Example #1 비열 비교하기

<?php
$a 
= array("apple""banana");
$b = array(=> "banana""0" => "apple");

var_dump($a == $b); // bool(true)
var_dump($a === $b); // bool(false)
?>

매뉴얼 배열형배열 함수 섹션을 참고하십시오.

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User Contributed Notes 7 notes

up
226
cb at netalyst dot com
16 years ago
The union operator did not behave as I thought it would on first glance. It implements a union (of sorts) based on the keys of the array, not on the values.

For instance:
<?php
$a
= array('one','two');
$b=array('three','four','five');

//not a union of arrays' values
echo '$a + $b : ';
print_r ($a + $b);

//a union of arrays' values
echo "array_unique(array_merge($a,$b)):";
// cribbed from http://oreilly.com/catalog/progphp/chapter/ch05.html
print_r (array_unique(array_merge($a,$b)));
?>

//output

$a + $b : Array
(
    [0] => one
    [1] => two
    [2] => five
)
array_unique(array_merge(Array,Array)):Array
(
    [0] => one
    [1] => two
    [2] => three
    [3] => four
    [4] => five
)
up
2
Anonymous
2 years ago
Merge two arrays and retain only unique values.
Append values from second array.
Do not care about keys.

<?php
$array1
= [
   
0 => 'apple',
   
1 => 'orange',
   
2 => 'pear',
];

$array2 = [
   
0 => 'melon',
   
1 => 'orange',
   
2 => 'banana',
];

$result = array_keys(
   
array_flip($array1) + array_flip($array2)
);
?>

Result:
[
  [0] => "apple",
  [1] => "orange",
  [2] => "pear",
  [3] => "melon",
  [4] => "banana",
}
up
40
Q1712 at online dot ms
17 years ago
The example may get u into thinking that the identical operator returns true because the key of apple is a string but that is not the case, cause if a string array key is the standart representation of a integer it's gets a numeral key automaticly.

The identical operator just requires that the keys are in the same order in both arrays:

<?php
$a
= array (0 => "apple", 1 => "banana");
$b = array (1 => "banana", 0 => "apple");

var_dump($a === $b); // prints bool(false) as well

$b = array ("0" => "apple", "1" => "banana");

var_dump($a === $b); // prints bool(true)
?>
up
22
dfranklin at fen dot com
20 years ago
Note that + will not renumber numeric array keys.  If you have two numeric arrays, and their indices overlap, + will use the first array's values for each numeric key, adding the 2nd array's values only where the first doesn't already have a value for that index.  Example:

$a = array('red', 'orange');
$b = array('yellow', 'green', 'blue');
$both = $a + $b;
var_dump($both);

Produces the output:

array(3) { [0]=>  string(3) "red" [1]=>  string(6) "orange" [2]=>  string(4) "blue" }

To get a 5-element array, use array_merge.

    Dan
up
16
Dan Patrick
12 years ago
It should be mentioned that the array union operator functions almost identically to array_replace with the exception that precedence of arguments is reversed.
up
5
xtpeqii at Hotmail dot com
7 years ago
$a=[ 3, 2, 1];
$b=[ 6, 5, 4];
var_dump( $a + $b );

output:
array(3) {
  [0]=>
  int(3)
  [1]=>
  int(2)
  [2]=>
  int(1)
}

The reason for the above output is that EVERY array in PHP is an associative one. 
Since the 3 elements in $b have the same keys( or numeric indices ) as those in $a, those elements in $b are ignored by the union operator.
up
15
amirlaher AT yahoo DOT co SPOT uk
22 years ago
[]= could be considered an Array Operator (in the same way that .= is a String Operator).
[]= pushes an element onto the end of an array, similar to array_push:
<?
  $array
= array(0=>"Amir",1=>"needs");
 
$array[]= "job";
 
print_r($array);
?>
Prints: Array ( [0] => Amir [1] => needs [2] => job )
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