Ah, yes, booleans - bit values that are either set (TRUE) or not set (FALSE). Now that we have 64 bit compilers using an int variable for booleans, there is *one* value which is FALSE (zero) and 2**64-1 values that are TRUE (everything else). It appears there's a lot more truth in this universe, but false can trump anything that's true...
PHP's handling of strings as booleans is *almost* correct - an empty string is FALSE, and a non-empty string is TRUE - with one exception: A string containing a single zero is considered FALSE. Why? If *any* non-empty strings are going to be considered FALSE, why *only* a single zero? Why not "FALSE" (preferably case insensitive), or "0.0" (with how many decimal places), or "NO" (again, case insensitive), or ... ?
The *correct* design would have been that *any* non-empty string is TRUE - period, end of story. Instead, there's another GOTCHA for the less-than-completely-experienced programmer to watch out for, and fixing the language's design error at this late date would undoubtedly break so many things that the correction is completely out of the question.
Speaking of GOTCHAs, consider this code sequence:
<?php
$x=TRUE;
$y=FALSE;
$z=$y OR $x;
?>
Is $z TRUE or FALSE?
In this case, $z will be FALSE because the above code is equivalent to <?php ($z=$y) OR $x ?> rather than <?php $z=($y OR $x) ?> as might be expected - because the OR operator has lower precedence than assignment operators.
On the other hand, after this code sequence:
<?php
$x=TRUE;
$y=FALSE;
$z=$y || $x;
?>
$z will be TRUE, as expected, because the || operator has higher precedence than assignment: The code is equivalent to $z=($y OR $x).
This is why you should NEVER use the OR operator without explicit parentheses around the expression where it is being used.
불린(Booleans)
이것은 아주 간단한 타입입니다. boolean 은 참(TRUE)과 거짓(FALSE)값을 표현합니다.
구문
boolean 을 나타내기 위해서는, 상수 TRUE 나 FALSE 을 사용합니다.
모두 대소문자를 구별하지 않습니다.
<?php
$foo = True; // TRUE 를 $foo 에 할당합니다.
?>
보통은, 연산자 가 리턴한 boolean 값이 조건문 에 전달 됩니다.
<?php
// == 는 테스트 연산자 입니다.
// 동일함을 비교하고, boolean 값을 리턴합니다.
if ($action == "show_version") {
echo "The version is 1.23";
}
// 이것은 불필요 합니다.
if ($show_separators == TRUE) {
echo "<hr>\n";
}
// ...왜냐하면 다음과 같이 해도 동일하기 때문입니다.:
if ($show_separators) {
echo "<hr>\n";
}
?>
불린(boolean)으로 변환
boolean 명시적으로 변환하기 위해서, (bool) 또는 (boolean) 캐스트를 사용합니다. 하지만, 보통의 경우에는 연산자, 함수, 조건문 이 boolean으로 자동으로 변환하므로 캐스트가 불필요 합니다.
참고 타입 다루기(juggling).
boolean 으로 변환할때, 다음 값들은 FALSE 로 간주 됩니다.:
-
boolean
FALSE - integer 0 (zero)
- float 0.0 (zero)
- 비어있는 string, 그리고 string "0"
- 요소를 가지지 않는 array
- 멤버 변수를 가지지 않는 object (PHP 4 에서만 적용)
- 특별한 타입 NULL (unset 변수 포함)
- 빈 태그로부터 만들어진 SimpleXML 객체
다른 모든 값들은 TRUE 로 간주 합니다. (모든 resource 를 포함해서)
Warning
-1 은 TRUE 로 간주됩니다, 0 이 아닌 다른 숫자들도 마찬가지입니다.
(양수이든 음수이든 상관 없음)!
<?php
var_dump((bool) ""); // bool(false)
var_dump((bool) 1); // bool(true)
var_dump((bool) -2); // bool(true)
var_dump((bool) "foo"); // bool(true)
var_dump((bool) 2.3e5); // bool(true)
var_dump((bool) array(12)); // bool(true)
var_dump((bool) array()); // bool(false)
var_dump((bool) "false"); // bool(true)
?>
add a note
User Contributed Notes 11 notes
Fred Koschara ¶
11 years ago
Mark Simon ¶
7 years ago
Note for JavaScript developers:
In PHP, an empty array evaluates to false, while in JavaScript an empty array evaluates to true.
In PHP, you can test an empty array as <?php if(!$stuff) …; ?> which won’t work in JavaScript where you need to test the array length.
This is because in JavaScript, an array is an object, and, while it may not have any elements, it is still regarded as something.
Just a trap for young players who routinely work in both langauges.
goran77 at fastmail dot fm ¶
8 years ago
Just something that will probably save time for many new developers: beware of interpreting FALSE and TRUE as integers.
For example, a small function for deleting elements of an array may give unexpected results if you are not fully aware of what happens:
<?php
function remove_element($element, $array)
{
//array_search returns index of element, and FALSE if nothing is found
$index = array_search($element, $array);
unset ($array[$index]);
return $array;
}
// this will remove element 'A'
$array = ['A', 'B', 'C'];
$array = remove_element('A', $array);
//but any non-existent element will also remove 'A'!
$array = ['A', 'B', 'C'];
$array = remove_element('X', $array);
?>
The problem here is, although array_search returns boolean false when it doesn't find specific element, it is interpreted as zero when used as array index.
So you have to explicitly check for FALSE, otherwise you'll probably loose some elements:
<?php
//correct
function remove_element($element, $array)
{
$index = array_search($element, $array);
if ($index !== FALSE)
{
unset ($array[$index]);
}
return $array;
}
asma dot gi dot 14 at gmail dot com ¶
3 years ago
Please keep in mind that the result of 0 == 'whatever' is true in PHP Version 7 and false in PHP version 8.
terminatorul at gmail dot com ¶
17 years ago
Beware that "0.00" converts to boolean TRUE !
You may get such a string from your database, if you have columns of type DECIMAL or CURRENCY. In such cases you have to explicitly check if the value is != 0 or to explicitly convert the value to int also, not only to boolean.
asma dot gi dot 14 at gmail dot com ¶
3 years ago
when using echo false; or print false; the display will be empty but when using echo 0; or print 0; the display will be 0.
Steve ¶
16 years ago
PHP does not break any rules with the values of true and false. The value false is not a constant for the number 0, it is a boolean value that indicates false. The value true is also not a constant for 1, it is a special boolean value that indicates true. It just happens to cast to integer 1 when you print it or use it in an expression, but it's not the same as a constant for the integer value 1 and you shouldn't use it as one. Notice what it says at the top of the page:
A boolean expresses a truth value.
It does not say "a boolean expresses a 0 or 1".
It's true that symbolic constants are specifically designed to always and only reference their constant value. But booleans are not symbolic constants, they are values. If you're trying to add 2 boolean values you might have other problems in your application.
Mark Simon ¶
7 years ago
Note on the OR operator.
A previous comment notes the trap you can fall into with this operator. This is about its usefulness.
Both OR and || are short-circuited operators, which means they will stop evaluating once they reach a TRUE value. By design, OR is evaluated after assignment (while || is evaluated before assignment).
This has the benefit of allowing some simple constructions such as:
<?php
$stuff=getStuff() or die('oops');
$thing=something() or $thing=whatever();
?>
The first example, often seen in PERL, could have been written as <?php if(!$stuff=getStuff()) die('oops'); ?> but reads a little more naturally. I have often used it in situations where null or false indicate failure.
The second allows for an alternative value if a falsy one is regarded as insufficient. The following example
<?php
$page=@$_GET['page'] or $page=@$_COOKIE['page'] or $page=1;
?>
is a simple way sequencing alternative values. (Note the usual warnings about using the @ operator or accepting unfiltered input …)
All this presupposes that 0 is also an unacceptable value in the situation.
Wackzingo ¶
16 years ago
It is correct that TRUE or FALSE should not be used as constants for the numbers 0 and 1. But there may be times when it might be helpful to see the value of the Boolean as a 1 or 0. Here's how to do it.
<?php
$var1 = TRUE;
$var2 = FALSE;
echo $var1; // Will display the number 1
echo $var2; //Will display nothing
/* To get it to display the number 0 for
a false value you have to typecast it: */
echo (int)$var2; //This will display the number 0 for false.
?>
artktec at gmail dot com ¶
17 years ago
Note you can also use the '!' to convert a number to a boolean, as if it was an explicit (bool) cast then NOT.
So you can do something like:
<?php
$t = !0; // This will === true;
$f = !1; // This will === false;
?>
And non-integers are casted as if to bool, then NOT.
Example:
<?php
$a = !array(); // This will === true;
$a = !array('a'); // This will === false;
$s = !""; // This will === true;
$s = !"hello"; // This will === false;
?>
To cast as if using a (bool) you can NOT the NOT with "!!" (double '!'), then you are casting to the correct (bool).
Example:
<?php
$a = !!array(); // This will === false; (as expected)
/*
This can be a substitute for count($array) > 0 or !(empty($array)) to check to see if an array is empty or not (you would use: !!$array).
*/
$status = (!!$array ? 'complete' : 'incomplete');
$s = !!"testing"; // This will === true; (as expected)
/*
Note: normal casting rules apply so a !!"0" would evaluate to an === false
*/
?>
marklgr ¶
9 years ago
For those wondering why the string "0" is falsy, consider that a good deal of input data is actually string-typed, even when it is semantically numeral.
PHP often tries to autoconvert these strings to numeral, as the programmer certainly intended (try 'echo "2"+3'). Consequently, PHP designers decided to treat 0 and "0" similarly, ie. falsy, for consistency and to avoid bugs where the programmer believes he got a true numeral that would happen to be truthy when zero.
