A leading zero in a numeric literal means "this is octal". But don't be confused: a leading zero in a string does not. Thus:
$x = 0123; // 83
$y = "0123" + 0 // 123
Integers
An integer is a number of the set ℤ = {..., -2, -1, 0, 1, 2, ...}.
See also:
Syntax
Integers can be specified in decimal (base 10), hexadecimal (base 16), octal (base 8) or binary (base 2) notation, optionally preceded by a sign (- or +).
Binary integer literals are available since PHP 5.4.0.
To use octal notation, precede the number with a 0 (zero). To use hexadecimal notation precede the number with 0x. To use binary notation precede the number with 0b.
Example #1 Integer literals
<?php
$a = 1234; // decimal number
$a = -123; // a negative number
$a = 0123; // octal number (equivalent to 83 decimal)
$a = 0x1A; // hexadecimal number (equivalent to 26 decimal)
$a = 0b11111111; // binary number (equivalent to 255 decimal)
?>
Formally, the structure for integer literals is:
decimal : [1-9][0-9]*
| 0
hexadecimal : 0[xX][0-9a-fA-F]+
octal : 0[0-7]+
binary : 0b[01]+
integer : [+-]?decimal
| [+-]?hexadecimal
| [+-]?octal
| [+-]?binary
The size of an integer is platform-dependent, although a maximum
value of about two billion is the usual value (that's 32 bits signed).
64-bit platforms usually have a maximum value of about 9E18, except on
Windows prior to PHP 7, where it was always 32 bit. PHP does not support
unsigned integers. Integer size can be determined
using the constant PHP_INT_SIZE, maximum value using
the constant PHP_INT_MAX since PHP 4.4.0 and PHP 5.0.5,
and minimum value using the constant PHP_INT_MIN since
PHP 7.0.0.
Warning
Prior to PHP 7, if an invalid digit was given in an octal integer (i.e. 8 or 9), the rest of the number was ignored. Since PHP 7, a parse error is emitted.
Integer overflow
If PHP encounters a number beyond the bounds of the integer type, it will be interpreted as a float instead. Also, an operation which results in a number beyond the bounds of the integer type will return a float instead.
Example #2 Integer overflow on a 32-bit system
<?php
$large_number = 2147483647;
var_dump($large_number); // int(2147483647)
$large_number = 2147483648;
var_dump($large_number); // float(2147483648)
$million = 1000000;
$large_number = 50000 * $million;
var_dump($large_number); // float(50000000000)
?>
Example #3 Integer overflow on a 64-bit system
<?php
$large_number = 9223372036854775807;
var_dump($large_number); // int(9223372036854775807)
$large_number = 9223372036854775808;
var_dump($large_number); // float(9.2233720368548E+18)
$million = 1000000;
$large_number = 50000000000000 * $million;
var_dump($large_number); // float(5.0E+19)
?>
There is no integer division operator in PHP. 1/2 yields the float 0.5. The value can be casted to an integer to round it towards zero, or the round() function provides finer control over rounding.
<?php
var_dump(25/7); // float(3.5714285714286)
var_dump((int) (25/7)); // int(3)
var_dump(round(25/7)); // float(4)
?>
Converting to integer
To explicitly convert a value to integer, use either the (int) or (integer) casts. However, in most cases the cast is not needed, since a value will be automatically converted if an operator, function or control structure requires an integer argument. A value can also be converted to integer with the intval() function.
If a resource is converted to an integer, then the result will be the unique resource number assigned to the resource by PHP at runtime.
See also Type Juggling.
From booleans
FALSE will yield 0 (zero), and TRUE will yield
1 (one).
From floating point numbers
When converting from float to integer, the number will be rounded towards zero.
If the float is beyond the boundaries of integer (usually +/- 2.15e+9 = 2^31 on 32-bit platforms and +/- 9.22e+18 = 2^63 on 64-bit platforms other than Windows), the result is undefined, since the float doesn't have enough precision to give an exact integer result. No warning, not even a notice will be issued when this happens!
Note:
As of PHP 7.0.0, instead of being undefined and platform-dependent, NaN and Infinity will always be zero when cast to integer.
Warning
Never cast an unknown fraction to integer, as this can sometimes lead to unexpected results.
<?php
echo (int) ( (0.1+0.7) * 10 ); // echoes 7!
?>
See also the warning about float precision.
From strings
From other types
Caution
The behaviour of converting to integer is undefined for other types. Do not rely on any observed behaviour, as it can change without notice.
add a note
User Contributed Notes 10 notes
php at richardneill dot org ¶
11 years ago
d_n at NOSPAM dot Loryx dot com ¶
17 years ago
Here are some tricks to convert from a "dotted" IP address to a LONG int, and backwards. This is very useful because accessing an IP addy in a database table is very much faster if it's stored as a BIGINT rather than in characters.
IP to BIGINT:
<?php
$ipArr = explode('.',$_SERVER['REMOTE_ADDR']);
$ip = $ipArr[0] * 0x1000000
+ $ipArr[1] * 0x10000
+ $ipArr[2] * 0x100
+ $ipArr[3]
;
?>
IP as BIGINT read from db back to dotted form:
Keep in mind, PHP integer operators are INTEGER -- not long. Also, since there is no integer divide in PHP, we save a couple of S-L-O-W floor (<division>)'s by doing bitshifts. We must use floor(/) for $ipArr[0] because though $ipVal is stored as a long value, $ipVal >> 24 will operate on a truncated, integer value of $ipVal! $ipVint is, however, a nice integer, so
we can enjoy the bitshifts.
<?php
$ipVal = $row['client_IP'];
$ipArr = array(0 =>
floor( $ipVal / 0x1000000) );
$ipVint = $ipVal-($ipArr[0]*0x1000000); // for clarity
$ipArr[1] = ($ipVint & 0xFF0000) >> 16;
$ipArr[2] = ($ipVint & 0xFF00 ) >> 8;
$ipArr[3] = $ipVint & 0xFF;
$ipDotted = implode('.', $ipArr);
?>
dhairya lakhera ¶
7 years ago
-------------------------------------------------------------------------
Question :
var_dump((int) 010); //Output 8
var_dump((int) "010"); //output 10
First one is octal notation so the output is correct. But what about the when converting "010" to integer. it should be also output 8 ?
--------------------------------------------------------------------------
Answer :
Casting to an integer using (int) will always cast to the default base, which is 10.
Casting a string to a number this way does not take into account the many ways of formatting an integer value in PHP (leading zero for base 8, leading "0x" for base 16, leading "0b" for base 2). It will simply look at the first characters in a string and convert them to a base 10 integer. Leading zeroes will be stripped off because they have no meaning in numerical values, so you will end up with the decimal value 10 for (int)"010".
Converting an integer value between bases using (int)010 will take into account the various ways of formatting an integer. A leading zero like in 010 means the number is in octal notation, using (int)010 will convert it to the decimal value 8 in base 10.
This is similar to how you use 0x10 to write in hexadecimal (base 16) notation. Using (int)0x10 will convert that to the base 10 decimal value 16, whereas using (int)"0x10" will end up with the decimal value 0: since the "x" is not a numerical value, anything after that will be ignored.
If you want to interpret the string "010" as an octal value, you need to instruct PHP to do so. intval("010", 8) will interpret the number in base 8 instead of the default base 10, and you will end up with the decimal value 8. You could also use octdec("010") to convert the octal string to the decimal value 8. Another option is to use base_convert("010", 8, 10) to explicitly convert the number "010" from base 8 to base 10, however this function will return the string "8" instead of the integer 8.
Casting a string to an integer follows the same the logic used by the intval function:
Returns the integer value of var, using the specified base for the conversion (the default is base 10).
intval allows specifying a different base as the second argument, whereas a straight cast operation does not, so using (int) will always treat a string as being in base 10.
php > var_export((int) "010");
10
php > var_export(intval("010"));
10
php > var_export(intval("010", 8));
8
ganlvtech at qq dot com ¶
4 years ago
Be aware of float to int cast overflow
<?php
// You may expected these
var_dump(0x7fffffffffffffff); // int(9223372036854775807)
var_dump(0x7fffffffffffffff + 1); // float(9.2233720368548E+18)
var_dump((int)(0x7fffffffffffffff + 1)); // int(9223372036854775807)
var_dump(0x7fffffffffffffff + 1 > 0); // bool(true)
var_dump((int)(0x7fffffffffffffff + 1) > 0); // bool(true)
var_dump((int)'9223372036854775807'); // int(9223372036854775807)
var_dump(9223372036854775808); // float(9.2233720368548E+18)
var_dump((int)'9223372036854775808'); // int(9223372036854775807)
var_dump((int)9223372036854775808); // int(9223372036854775807)
// But actually, it likes these
var_dump(0x7fffffffffffffff); // int(9223372036854775807)
var_dump(0x7fffffffffffffff + 1); // float(9.2233720368548E+18)
var_dump((int)(0x7fffffffffffffff + 1)); // int(-9223372036854775808) <-----
var_dump(0x7fffffffffffffff + 1 > 0); // bool(true)
var_dump((int)(0x7fffffffffffffff + 1) > 0); // bool(false) <-----
var_dump((int)'9223372036854775807'); // int(9223372036854775807)
var_dump(9223372036854775808); // float(9.2233720368548E+18)
var_dump((int)'9223372036854775808'); // int(9223372036854775807)
var_dump((int)9223372036854775808); // int(-9223372036854775808) <-----
?>
These overflows are dangerous when you try to compare it with zero, or substract it from another value (e.g. money).
egwayjen at gmail dot com ¶
7 years ago
"There is no integer division operator in PHP". But since PHP 7, there is the intdiv function.
litbai ¶
8 years ago
<?php
$ipArr = explode('.', $ipString);
$ipVal = ($ipArr[0] << 24)
+ ($ipArr[1] << 16)
+ ($ipArr[2] << 8)
+ $ipArr[3]
;
?>
1. the priority of bit op is lower than '+',so there should be brackets.
2. there is no unsighed int in PHP, if you use 32 bit version，the code above will get negative result when the first position of IP string greater than 127.
3. what the code actually do is calculate the integer value of transformed 32 binary bit from IP string.
Anonymous ¶
9 years ago
Converting to an integer works only if the input begins with a number
(int) "5txt" // will output the integer 5
(int) "before5txt" // will output the integer 0
(int) "53txt" // will output the integer 53
(int) "53txt534text" // will output the integer 53
rustamabd@gmail-you-know-what ¶
18 years ago
Be careful with using the modulo operation on big numbers, it will cast a float argument to an int and may return wrong results. For example:
<?php
$i = 6887129852;
echo "i=$i\n";
echo "i%36=".($i%36)."\n";
echo "alternative i%36=".($i-floor($i/36)*36)."\n";
?>
Will output:
i=6.88713E+009
i%36=-24
alternative i%36=20
Anonymous ¶
17 years ago
To force the correct usage of 32-bit unsigned integer in some functions, just add '+0' just before processing them.
for example
echo(dechex("2724838310"));
will print '7FFFFFFF'
but it should print 'A269BBA6'
When adding '+0' php will handle the 32bit unsigned integer
correctly
echo(dechex("2724838310"+0));
will print 'A269BBA6'
