SQLite3::query

(PHP 5 >= 5.3.0, PHP 7)

SQLite3::queryExecutes an SQL query

설명

public SQLite3Result SQLite3::query ( string $query )

Executes an SQL query, returning an SQLite3Result object if the query returns results.

인수

query

The SQL query to execute.

반환값

Returns an SQLite3Result object if the query returns results. Otherwise, returns TRUE if the query succeeded, FALSE on failure.

예제

Example #1 SQLite3::query() example

<?php
$db 
= new SQLite3('mysqlitedb.db');

$results $db->query('SELECT bar FROM foo');
while (
$row $results->fetchArray()) {
    
var_dump($row);
}
?>

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User Contributed Notes 2 notes

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42
bohwaz
11 years ago
The recommended way to do a SQLite3 query is to use a statement. For a table creation, a query might be fine (and easier) but for an insert, update or select, you should really use a statement, it's really easier and safer as SQLite will escape your parameters according to their type. SQLite will also use less memory than if you created the whole query by yourself. Example:

<?php

$db
= new SQLite3;
$statement = $db->prepare('SELECT * FROM table WHERE id = :id;');
$statement->bindValue(':id', $id);

$result = $statement->execute();

?>

You can also re-use a statement and change its parameters, just do $statement->reset(). Finally don't forget to close a statement when you don't need it anymore as it will free some memory.
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0
paule-panke at example dot com
7 years ago
Check with SQLite3Result::numColumns() for an empty result before calling SQLite3Result::fetchArray().

In contrast to the documentation SQLite3::query() always returns a SQLite3Result instance, not only for queries returning rows (SELECT, EXPLAIN). Each time SQLite3Result::fetchArray() is called on a result from a result-less query internally the query is executed again, which will most probably break your application.
For a framwork or API it's not possible to know in before whether or not a query will return rows (SQLite3 supports multi-statement queries). Therefore the argument "Don't execute query('CREATE ...')" is not valid.
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