imagecolorallocatealpha

(PHP 4 >= 4.3.2, PHP 5, PHP 7)

imagecolorallocatealpha — Allocate a color for an image

Descrierea

imagecolorallocatealpha ( resource $image , int $red , int $green , int $blue , int $alpha ) : int

imagecolorallocatealpha() behaves identically to imagecolorallocate() with the addition of the transparency parameter alpha.

Parametri

image: O resursă - imagine, întoarsă de una din funcțiile de creare a imaginilor, cum ar fi imagecreatetruecolor().
red: Valoarea componentei roșii.
green: Valoarea componentei verzi.
blue: Valoarea componentei albastre.
alpha: A value between 0 and 127. 0 indicates completely opaque while 127 indicates completely transparent.

The red, green and blue parameters are integers between 0 and 255 or hexadecimals between 0x00 and 0xFF.

Valorile întoarse

A color identifier or false if the allocation failed.

Avertizare

Această funcție poate întoarce valoarea Boolean false, dar poate de asemenea întoarce o valoare non-Boolean care evaluează în false. Vă rugăm să citiți secțiunea despre tipul Boolean pentru informații suplimentare. Utilizați operatorul === pentru a verifica valoarea întoarsă de această funcție.

Exemple

Example #1 Example of using imagecolorallocatealpha()


<?php
$size = 300;
$image=imagecreatetruecolor($size, $size);

// something to get a white background with black border
$back = imagecolorallocate($image, 255, 255, 255);
$border = imagecolorallocate($image, 0, 0, 0);
imagefilledrectangle($image, 0, 0, $size - 1, $size - 1, $back);
imagerectangle($image, 0, 0, $size - 1, $size - 1, $border);

$yellow_x = 100;
$yellow_y = 75;
$red_x    = 120;
$red_y    = 165;
$blue_x   = 187;
$blue_y   = 125;
$radius   = 150;

// allocate colors with alpha values
$yellow = imagecolorallocatealpha($image, 255, 255, 0, 75);
$red    = imagecolorallocatealpha($image, 255, 0, 0, 75);
$blue   = imagecolorallocatealpha($image, 0, 0, 255, 75);

// drawing 3 overlapped circle
imagefilledellipse($image, $yellow_x, $yellow_y, $radius, $radius, $yellow);
imagefilledellipse($image, $red_x, $red_y, $radius, $radius, $red);
imagefilledellipse($image, $blue_x, $blue_y, $radius, $radius, $blue);

// don't forget to output a correct header!
header('Content-Type: image/png');

// and finally, output the result
imagepng($image);
imagedestroy($image);
?>

Exemplul de mai sus va afișa ceva similar cu:

Output of example : Example of using imagecolorallocatealpha()

Example #2 Convert typical alpha values for use with imagecolorallocatealpha()

Usually alpha values of 0 designate fully transparent pixels, and the alpha channel has 8 bits. To convert such alpha values to be compatible with imagecolorallocatealpha(), some simple arithmetic is sufficient:


<?php
$alpha8 = 0; // fully transparent
var_dump(127 - ($alpha8 >> 1));
$alpha8 = 255; // fully opaque
var_dump(127 - ($alpha8 >> 1));
?>

Exemplul de mai sus va afișa:

int(127)
int(0)

A se vedea și

imagecolorallocate() - Allocate a color for an image
imagecolordeallocate() - De-allocate a color for an image

add a note

User Contributed Notes 3 notes

down

eric (at) junioronline.us ¶

18 years ago


If you only wish to extract the alpha value for a color, you can simply extract it like so:

<?php

    $color = imagecolorat($im, 50, 50);
    $alpha = $color >> 24;

?>

It actually shifts off the first 24 bits (where 8x3 are used for each color), and returns the remaining 7 allocated bits (commonly used for alpha)

down

Brett G ¶

9 years ago


When working with transparency, avoid imagecreate() and use imagecreatetruecolor() instead. Transparency effects may not work as expected within a palette-based image.

down

fjoggen at gmail dot com ¶

16 years ago


If you need to calculate the integer representation of a color with an alpha channel, without initialising an image and using the imagecolorallocatealpha function. Then this function might be of some help:

<?php
function alphaColor($hexColor,$alpha)
{
        return bindec(decbin($alpha).decbin(hexdec($hexColor));
}

echo alphaColor("FFFFFF",127);
?>

add a note