This no longer uses the fill color. It now uses the stroke color, consistent with the documentation.
ImagickDraw::point
(PECL imagick 2, PECL imagick 3)
ImagickDraw::point — Draws a point
Descrierea
public ImagickDraw::point
( float
$x
, float $y
) : boolAvertizare
Această funcție nu este documentată în prezent; este disponibilă numai lista sa de argumente.
Draws a point using the current stroke color and stroke thickness at the specified coordinates.
Parametri
-
x -
point's x coordinate
-
y -
point's y coordinate
Valorile întoarse
Nu este întoarsă nici o valoare.
Exemple
Example #1 ImagickDraw::point()
<?php
function point($fillColor, $backgroundColor) {
$draw = new \ImagickDraw();
$draw->setFillColor($fillColor);
for ($x = 0; $x < 10000; $x++) {
$draw->point(rand(0, 500), rand(0, 500));
}
$imagick = new \Imagick();
$imagick->newImage(500, 500, $backgroundColor);
$imagick->setImageFormat("png");
$imagick->drawImage($draw);
header("Content-Type: image/png");
echo $imagick->getImageBlob();
}
?>
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User Contributed Notes 2 notes
Brian ¶
11 years ago
spz ¶
15 years ago
point($x, $y) uses the FillColor of ImagickDraw! This actually took quite a while, till I found out that it's falsely documented on these pages. So to draw single pixels, do it like this:
<?php
$image = new Imagick();
$draw = new ImagickDraw();
$pixel = new ImagickPixel('red');
$image->newImage(10, 10, 'transparent', 'gif');
// Here comes the magick:
$pixel->setColor($_POST[$i."x".$j]);
$draw->setFillColor($pixel);
$draw->point($i,$j);
$image->drawImage($draw);
$image->writeImages($path, true);
?>
