I couldn't find any how-to example for getting the filenames, so I made an easy one.
Here's an example how to list all filenames from a zip-archive:
<?php
$zip = new ZipArchive;
if ($zip->open('items.zip'))
{
for($i = 0; $i < $zip->numFiles; $i++)
{
echo 'Filename: ' . $zip->getNameIndex($i) . '<br />';
}
}
else
{
echo 'Error reading zip-archive!';
}
?>
Hope it helps.
ZipArchive::getNameIndex
(PHP 5 >= 5.2.0, PHP 7, PECL zip >= 1.5.0)
ZipArchive::getNameIndex — Returns the name of an entry using its index
Descrierea
public ZipArchive::getNameIndex
( int
$index
, int $flags = ?
) : string|falseReturns the name of an entry using its index.
Parametri
-
index -
Index of the entry.
-
flags -
If flags is set to
ZipArchive::FL_UNCHANGED, the original unchanged name is returned.
Valorile întoarse
Returns the name on success sau false în cazul eșecului.
Exemple
Example #1 ZipArchive::getNameIndex() example
<?php
if ($zip->open('test.zip') == TRUE) {
for ($i = 0; $i < $zip->numFiles; $i++) {
$filename = $zip->getNameIndex($i);
// ...
}
}
?>
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User Contributed Notes 1 note
Yeslifer ¶
15 years ago
