date_parse

(PHP 5 >= 5.2.0, PHP 7, PHP 8)

date_parse — 返回指定日期/时间的详细信息的关联数组

说明

date_parse(string $datetime): array

date_parse() 根据与 strtotime() 和 DateTimeImmutable::__construct() 相同的规则解析指定 datetime 字符串。它不返回 Unix 时间戳（使用 strtotime()）或者 DateTimeImmutable 对象（使用 DateTimeImmutable::__construct()），而是返回包含在指定 datetime 字符串中检测到相关信息的关联数组。

如果找不到某组元素的信息，那么这些数组元素将会设置为 false 或缺失。如果需要从相同的 datetime 字符串构建时间戳或者 DateTimeImmutable 对象，需要将更多字段设置为非 false 值。查看以下示例以了解情况。

参数

datetime: DateTimeImmutable::__construct() 接受的日期/时间格式。

返回值

返回 array，包含解析日期/时间的信息。

返回的数组存在以下键 year、month、day、hour、minute、second、fraction 和 is_localtime。

如果存在 is_localtime，则 zone_type 表示时区类型。类型 1（UTC 时差），添加 zone、is_dst；类型 2（时区缩写），添加 tz_abbr、is_dst；类型 3（时区标识符），添加 tz_abbr、tz_id。

如果 datetime 字符串存在类似 +3 days 这样的相对时间元素，则返回的数组则包含键为 relative 的嵌套数组。然后此数组将包含如下键 year、month、day、hour、minute、second，如果必要还会包含 weekday 和 weekdays，具体取决于传入的字符串。

数组包含 warning_count 和 warnings 字段。第一个表示发现了多少警告。元素 warnings 的键表示指定 datetime 发生警告的位置，值为字符串，描述警告本身。

数组也包含 error_count 和 errors 字段。第一个表示发现了多少错误。元素 errors 的键表示指定 datetime 发生错误的位置，值为字符串，描述错误本身。

警告

如果同一个位置存在多个警告/错误，那么 warnings 和 errors 数组中元素的数量可能会少于 warning_count 或者 error_count。

错误／异常

date/time 的格式有错误时，返回数组的 'errors' 键将包含错误信息。

更新日志

版本	说明
7.2.0	返回数组的 `zone` 键现在代表秒，而不是分钟。并且正负符号已反转，例如：之前是 `-120` 现在是 `7200`。

示例

示例 #1 具有全面的 datetime 字符串的 date_parse() 示例

<?php
var_dump(date_parse("2006-12-12 10:00:00.5"));
?>

以上示例会输出：

array(12) {
  ["year"]=>
  int(2006)
  ["month"]=>
  int(12)
  ["day"]=>
  int(12)
  ["hour"]=>
  int(10)
  ["minute"]=>
  int(0)
  ["second"]=>
  int(0)
  ["fraction"]=>
  float(0.5)
  ["warning_count"]=>
  int(0)
  ["warnings"]=>
  array(0) {
  }
  ["error_count"]=>
  int(0)
  ["errors"]=>
  array(0) {
  }
  ["is_localtime"]=>
  bool(false)
}

如果在指定 datetime 字符串中出现时区元素，那才会展示。在这种情况下，总会存在 zone_type 和更多元素，具体取决于其值。

示例 #2 带时区缩写信息的 date_parse()

<?php
var_dump(date_parse("June 2nd, 2022, 10:28:17 BST"));
?>

以上示例会输出：

array(16) {
  ["year"]=>
  int(2022)
  ["month"]=>
  int(6)
  ["day"]=>
  int(2)
  ["hour"]=>
  int(10)
  ["minute"]=>
  int(28)
  ["second"]=>
  int(17)
  ["fraction"]=>
  float(0)
  ["warning_count"]=>
  int(0)
  ["warnings"]=>
  array(0) {
  }
  ["error_count"]=>
  int(0)
  ["errors"]=>
  array(0) {
  }
  ["is_localtime"]=>
  bool(true)
  ["zone_type"]=>
  int(2)
  ["zone"]=>
  int(0)
  ["is_dst"]=>
  bool(true)
  ["tz_abbr"]=>
  string(3) "BST"
}

示例 #3 带时区标识符信息的 date_parse()

<?php
var_dump(date_parse("June 2nd, 2022, 10:28:17 Europe/London"));
?>

以上示例会输出：

array(14) {
  ["year"]=>
  int(2022)
  ["month"]=>
  int(6)
  ["day"]=>
  int(2)
  ["hour"]=>
  int(10)
  ["minute"]=>
  int(28)
  ["second"]=>
  int(17)
  ["fraction"]=>
  float(0)
  ["warning_count"]=>
  int(0)
  ["warnings"]=>
  array(0) {
  }
  ["error_count"]=>
  int(0)
  ["errors"]=>
  array(0) {
  }
  ["is_localtime"]=>
  bool(true)
  ["zone_type"]=>
  int(3)
  ["tz_id"]=>
  string(13) "Europe/London"
}

如果解析的 datetime 字符串越小，那么可用的信息就越少。再本示例中，所有时间部分都返回为 false。

示例 #4 带最小字符串的 date_parse()

<?php
var_dump(date_parse("June 2nd, 2022"));
?>

以上示例会输出：

array(12) {
  ["year"]=>
  int(2022)
  ["month"]=>
  int(6)
  ["day"]=>
  int(2)
  ["hour"]=>
  bool(false)
  ["minute"]=>
  bool(false)
  ["second"]=>
  bool(false)
  ["fraction"]=>
  bool(false)
  ["warning_count"]=>
  int(0)
  ["warnings"]=>
  array(0) {
  }
  ["error_count"]=>
  int(0)
  ["errors"]=>
  array(0) {
  }
  ["is_localtime"]=>
  bool(false)
}

相对格式不会影响从绝对格式格式化的值，但会被解析为“relative”元素。

示例 #5 带相对格式的 date_parse()

<?php
var_dump(date_parse("2006-12-12 10:00:00.5 +1 week +1 hour"));
?>

以上示例会输出：

array(13) {
  ["year"]=>
  int(2006)
  ["month"]=>
  int(12)
  ["day"]=>
  int(12)
  ["hour"]=>
  int(10)
  ["minute"]=>
  int(0)
  ["second"]=>
  int(0)
  ["fraction"]=>
  float(0.5)
  ["warning_count"]=>
  int(0)
  ["warnings"]=>
  array(0) {
  }
  ["error_count"]=>
  int(0)
  ["errors"]=>
  array(0) {
  }
  ["is_localtime"]=>
  bool(false)
  ["relative"]=>
  array(6) {
    ["year"]=>
    int(0)
    ["month"]=>
    int(0)
    ["day"]=>
    int(7)
    ["hour"]=>
    int(1)
    ["minute"]=>
    int(0)
    ["second"]=>
    int(0)
  }
}

在某些时候，比如 Thursday 将会设置字符串的时间部分设置为 0。如果 Thursday 传递给 DateTimeImmutable::__construct() 也会导致小时，分钟，秒和小数部分设置为 0。下面的示例中，year 元素将设置为 false。

示例 #6 date_parse() with side-effects

<?php
var_dump(date_parse("Thursday, June 2nd"));
?>

以上示例会输出：

array(13) {
  ["year"]=>
  bool(false)
  ["month"]=>
  int(6)
  ["day"]=>
  int(2)
  ["hour"]=>
  int(0)
  ["minute"]=>
  int(0)
  ["second"]=>
  int(0)
  ["fraction"]=>
  float(0)
  ["warning_count"]=>
  int(0)
  ["warnings"]=>
  array(0) {
  }
  ["error_count"]=>
  int(0)
  ["errors"]=>
  array(0) {
  }
  ["is_localtime"]=>
  bool(false)
  ["relative"]=>
  array(7) {
    ["year"]=>
    int(0)
    ["month"]=>
    int(0)
    ["day"]=>
    int(0)
    ["hour"]=>
    int(0)
    ["minute"]=>
    int(0)
    ["second"]=>
    int(0)
    ["weekday"]=>
    int(4)
  }
}

参见

date_parse_from_format() - Get info about given date formatted according to the specified format，以解析具有特定格式的datetime
checkdate() - 验证一个格里高里日期，以便于公历日期验证
getdate() - 获取日期/时间信息

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User Contributed Notes 11 notes

down

admin at torntech dot com ¶

14 years ago


A warning to others. Some keys will return with a default value where others will return as false if the date string has it omitted. Unsure if this is a bug or feature, but hopefully this will save someone some time.
<?php
///Example
$input = "Feb 2010";
$info = date_parse($input);
var_dump($info);

/*Returns:
array(12) { 
    ["year"]=> int(2010)
    ["month"]=> int(2)
    ["day"]=> int(1)    //<---expected false like below
    ["hour"]=> bool(false)
    ["minute"]=> bool(false)
    ["second"]=> bool(false)
    ["fraction"]=> bool(false)
    ["warning_count"]=> int(0)
    ["warnings"]=> array(0) { }
    ["error_count"]=> int(0)
    ["errors"]=> array(0) { }
    ["is_localtime"]=> bool(false)
}*/
?>

down

alvaro at demogracia dot com ¶

13 years ago


Be aware that date_parse() is happy with just a time zone and it can be pretty counter-intuitive. E.g.:

<?php
var_dump( date_parse('Europe/Madrid') );
?>

... prints an array where year, month, day... are FALSE. But so do these:

<?php
var_dump( date_parse('A') );
var_dump( date_parse('B') );
var_dump( date_parse('X') );
?>

Don't forget to further validate date_parse()'s output even when it isn't FALSE and the 'errors' key is empty.

down

thisismelennart dot borgman at gmail dot com ¶

10 years ago


Here is a workaround for the "Feb 2010" problem. It also handles "2014".

http://stackoverflow.com/questions/27052374/php-date-parsefeb-2010-gives-day-1/27068409

down

edg at greenberg dot org ¶

6 years ago


Passing "YYYY-MM" results in a valid date. Be careful to validate that your submitted date passed YOUR requirements.

down

paul at juniperwebcraft dot com ¶

7 years ago

down

y dot adounis at gmail dot com ¶

4 years ago


Developers, be aware that using "now" will return an empty array, ex :

<?php
date_parse("now");
?>

Will return :

Array
(
    [year] => 
    [month] => 
    [day] => 
    [hour] => 
    [minute] => 
    [second] => 
    [fraction] => 
    [warning_count] => 0
    [warnings] => Array
        (
        )

    [error_count] => 0
    [errors] => Array
        (
        )

    [is_localtime] => 
)

down

ryan_a_martin at yahoo dot com ¶

13 years ago


See checkdate() at http://php.net/manual/en/function.checkdate.php for Gregorian date validation.

down

gpayne at galenaparkisd com ¶

17 years ago


Careful - date_parse is perfectly happy with something like this:

 date_parse("2006-2-31");

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-2

adamm at extratech dot com ¶

12 years ago


A warning to some
<?php
$time = "00:14:38"
$parse_date = date_parse($time);
echo var_dump($parse_date) ."<br>";
//here you will get what you expect

$time = "-00:14:38"
$parse_date = date_parse($time);
echo var_dump($parse_date) ."<br>";
//here you will recieve hours minutes and seconds as booleans and as false and you will get error set to "Unexpected character"

$time = "00:-14:38"
$parse_date = date_parse($time);
echo var_dump($parse_date) ."<br>";
//here you will recieve the same as the above

$time = "00:14:-38"
$parse_date = date_parse($time);
echo var_dump($parse_date) ."<br>";
//here you will receive hours as 00 minutes as 14 and seconds as 0. The error will get set as the same as above. Meaning "Unexpected character"
?>

down

-5

alan at wilcoxengineering dot com ¶

15 years ago


Caution: date_parse expects months 1..12 only.

date_parse("13/1/5769")  for  month=13, Ehul in Jewish calendar, results in  month==3 instead of month==13.

It does, however, report the error array showing "Unexpected Character."

It would be nice if date_parse could handle the months properly (just report back a "13" for the month). The older approach of substr() is my workaround.

down

-4

eugene at ultimatecms dot co dot za ¶

14 years ago


<?php

$ida = '091122671325';
$idb = '091123671325';

// This function will match the identity number up to the day, but only for a maximum of 99years+364days.
// Will not work when checking persons older than 100years-1day.

function idtodate($id)
{
        $year = date("Y");
        $month = date("m");
        $day = date("d");

        $nc = substr($year, 0, 2);
        $ny = substr($year, 2, 2);

        $y = substr($id, 0, 2);
        $m = substr($id, 2, 2);
        $d = substr($id, 4, 2);

        if($y.$m.$d <= $ny.$month.$day-1) {
                $newc = $nc;
        } else {
                $newc = $nc-1;
        }

        $new = $newc.$y;

        return array('year' => $new, 'month' => $m, 'day' => $d);
}

echo 'ID: '.$ida.'<br>';
print_r(idtodate($ida));

echo '<br><br>';

echo 'ID: '.$idb.'<br>';
print_r(idtodate($idb));

?>

Output:
1. If the year-month-day is smaller than today (2009-11-23), but bigger than 1999: year => 2009
ID: 091122671325
Array ( [year] => 2009 [month] => 11 [day] => 22 )

2. If the year-month-day is the same as, or bigger than today, but smaller than 2000: year => 1909
ID: 091123671325
Array ( [year] => 1909 [month] => 11 [day] => 23 )

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