Seemingly, you can't omit the width the same way you do with the height. If you write -1 for the width and specify a number for the height it will return false
(PHP 5 >= 5.5.0, PHP 7)
imagescale — Scale an image using the given new width and height
$image
, int $new_width
[, int $new_height
= -1
[, int $mode
= IMG_BILINEAR_FIXED
]] )imagescale() scales an image using the given interpolation algorithm.
image
imagecreatetruecolor() 등의 이미지 생성 함수에서 반환한 이미지 자원.
new_width
The width to scale the image to.
new_height
The height to scale the image to. If omitted or negative, the aspect ratio will be preserved.
You should always provide the height if using PHP 5.5.18 or earlier, or PHP 5.6.2 or earlier, as the aspect ratio calculation was incorrect.
mode
One of IMG_NEAREST_NEIGHBOUR
,
IMG_BILINEAR_FIXED
,
IMG_BICUBIC
,
IMG_BICUBIC_FIXED
or anything else (will use two
pass).
Note:
IMG_WEIGHTED4
is not yet supported.
Return the scaled image resource on success실패 시 FALSE
를 반환합니다.
버전 | 설명 |
---|---|
5.5.19/5.6.3 |
The calculation of the height if new_height was
negative or omitted was fixed; prior to these versions, the aspect
ratio was not maintained correctly.
|