mysql_insert_id

(PHP 4, PHP 5)

mysql_insert_id이전의 INSERT 작업으로부터 생성된 ID를 반환

설명

int mysql_insert_id ([ resource $link_identifier ] )

이전의 INSERT 질의로부터 AUTO_INCREMENT 컬럼에 의해 생성된 ID를 반환한다.

인수

link_identifier

MySQL 연결. 지정하지 않으면 mysql_connect()로 연 마지막 연결을 사용합니다. 연결이 없으면, 인수 없이 mysql_connect()를 호출하여 연결을 만듭니다. 연결이 성립되지 않으면 E_WARNING 등급의 오류를 생성합니다.

반환값

성공하면 이전의 INSERT 질의에 의한 AUTO_INCREMENT 컬럼으로부터 생성된 ID를, 이전 질의로부터 AUTO_INCREMENT 값이 생성되지 않았다면, 0을, MySQL 접속이 되지 않은 상태였다면 FALSE를 반환한다.

예제

Example #1 mysql_insert_id() 예제

<?php
$link 
mysql_connect('localhost''mysql_user''mysql_password');
if (!
$link) {
    die(
'Could not connect: ' mysql_error());
}
mysql_select_db('mydb');

mysql_query("INSERT INTO mytable (product) values ('kossu')");
printf("Last inserted record has id %d\n"mysql_insert_id());
?>

주의

Caution

mysql_insert_id()는 원시(native) MySQL C API 함수인 mysql_insert_id()long형태의 반환값을 PHP의 int로 변환한다. AUTO_INCREMENT 컬럼이 BIGINT이면, mysql_insert_id()에 의해 반환되는 값은 잘못될 것이다. 이경우, MySQL SQL 내부 함수인 LAST_INSERT_ID()를 사용하면 된다.

Note:

mysql_insert_id()는 최근 수행한 질의에 대해서 동작하기 때문에, 생성된 값은 질의 직후에 mysql_insert_id()를 호출해야 된다.

Note:

MySQL SQL 함수인 LAST_INSERT_ID()는 가장 최근에 생성된 AUTO_INCREMENT 값을 담고 있으며, 질의 간에 지워지지는 않는다.

참고

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User Contributed Notes 12 notes

up
6
Alfred Nony Mouse
16 years ago
There's nothing inherently wrong with using auto-increment fields. There's also nothing wrong with the main competetive idea, which is for the database to supply a primitive sequence of non-repeating identifiers, typically integers. This is rather like which side of the road you drive on.

The bigger problem is when people don't understand what they are doing with database access. It's like driving a car without really knowing the rules of the road. Such people wind up making bad decisions without realizing it, and then, eventually, something breaks.

Databases are complex beasts, and worth taking the time to really understand. Learn about the implications and limitations of different approaches to solving problems. Then, you will be prepared to pick a solution based on what has to work.
up
5
foros (_AT_) anthalia.com
17 years ago
Forget about using MAX to get the last inserted id. Race conditions like other users inserting between your SELECT MAX(.. and your INSERT may render your id unusable.

The WAY to get the id is by using mysql_insert_id() or the mysql SQL function LAST_INSERT_ID().

Take care, if using mysql_insert_id() you should provide the resource returned by the mysql_connect, not the resultset returned by mysql_query.
up
2
elinor dot hurst at REMOVETHIS dot gmail dot com
16 years ago
I don't get all the fuss around this.

I read:
"The value of mysql_insert_id() is affected only by statements issued within the current client connection. It is not affected by statements issued by other clients."

See: http://dev.mysql.com/doc/refman/5.0/es/mysql-insert-id.html

I can't really see what's inaccurate about that.

"In the case of a multiple-row INSERT statement, mysql_insert_id() returns the first automatically generated AUTO_INCREMENT value; if no such value is generated, it returns the last last explicit value inserted into the AUTO_INCREMENT column."

I must be missing something here but why would you insert multiple rows and then only handle the last one with some favoured behaviour? You could just as well insert them one at a time and then handle each row separately with the latest id.

I can't see what's wrong with that.

However I can see what's wrong with simply using max(my_table.id_column) because of the concurrent access issues this would imply.
up
1
athies at gmail dot com
19 years ago
Just a quick note. mysql_insert_id() does work with REPLACE.
up
0
bargainbatman at gmail dot com
15 years ago
I thought this would be relevant to all the people using mysqli and looking for the ID after INSERT command :

<?php
function insert_join($catid, $disc_id) {
// insert a new item into the database
  
$conn = db_connect();
  
// insert new item
  
$demande = "insert into categories_disc values ('', '".$catid."', '".$disc_id."')";
  
$resultat = $conn->query($demande);
   if (!
$resultat) {
     return
false;
   } else {
    return
$conn->insert_id; // function will now return the ID instead of true.
}

}
?>

Then, on the other side, let us call this function as follows :

<?php
$cat_id
= insert_join($catid, $disc_id);
if(
$cat_id !== false) {
   
        echo
"<p>Category stuff was added to the database as follows : <br>";
        echo
"<hr>ID de la category : ".$cat_id."</p><hr>";

        }
?>
up
-2
Anonymous
19 years ago
Take care of setting an empty value for the AUTO_INCREMENT Field else you never get a value except zero returned from mysq_insert_id() ....

Ciao Ephraim
up
-3
heiligkind at yahoo dot de
19 years ago
If you insert a data row by using the ON DUPLICATE KEY UPDATE clause in an INSERT-statement, the mysql_insert_id() function will return not the same results as if you directly use LAST_INSERT_ID() in MySQL.

See the following example:

<?
  
// insert a datarow, primary key is auto_increment
   // value is a unique key
  
$query = "INSERT INTO test (value) VALUES ('test')";
  
mysql_query( $query );

   echo
'LAST_INSERT_ID: ',
         
mysql_query( "SELECT LAST_INSERT_ID()" ),
         
'<br>mysql_insert_id: ',
         
mysql_insert_id();

?>

This will print:

LAST_INSERT_ID: 1
mysql_insert_id: 1

In this case the function returns the same as the MySQL-Statement.
But see the insert on an existing key:

<?
   $query
= "INSERT INTO test (value)
                  VALUES ('test')
                  ON DUPLICATE KEY UPDATE value = 'test2'"
;
  
mysql_query( $query );

   echo
'LAST_INSERT_ID: ',
         
mysql_query( "SELECT LAST_INSERT_ID()" ),
         
'<br>mysql_insert_id: ',
         
mysql_insert_id();

?>

This will print:

LAST_INSERT_ID: 2
mysql_insert_id: 1

By using the ON DUPLICATE KEY UPDATE clause, only the old datarow will be modified, if the INSERT statement causes a duplicate entry, but the LAST_INSERT_ID() function returns the next auto_increment value for the primary key, which is by the way not set as the next auto_increment value in the database.

The mysql_insert_id() function returns the primary key of the old (and changed) data row. For me this is the right operation method, because the LAST_INSERT_ID() function returns a value which is not referenced to a data row at all.

Greets from Munich.

heiligkind
up
-3
hoangvu4000 at gmail dot com
11 years ago
How to get ID of the last updated row in MySQL?

75
down vote
I've found an answer to this problem :)

by Pomyk

SET @update_id := 0;
UPDATE some_table SET row = 'value', id = (SELECT @update_id := id)
WHERE some_other_row = 'blah' LIMIT 1;
SELECT @update_id;
EDIT by aefxx

This technique can be further expanded to retrieve the ID of every row affected by an update statement:

SET @uids := null;
UPDATE footable
   SET foo = 'bar'
WHERE fooid > 5
   AND ( SELECT @uids := CONCAT_WS(',', fooid, @uids) );
SELECT @uids;
This will return a string with all the IDs concatenated by a colon.

(questions: 1388025  form stackoverflow)
up
-3
louis at intoplay dot com
17 years ago
If mysql_insert_id() returns 0 or null, check your auto increment field is not being set by your sql query, also if you have multiple db connections like I did, the solution is to create a seperate db connection for this query.
up
-4
vksgeneric at hotmail dot com
25 years ago
You can't do an INSERT DELAYED and expect to get anything but zero, for it runs in a separate thread, and mysql_insert_id() is tied to the current thread.
Vlad
up
-5
dhiraj dot webdeveloper at gmail dot com
7 years ago
MySQLi Procedural
//---------------------------------------------
$last_id = mysqli_insert_id($conn);

//---------------------------------------------
<?php
$servername
= "localhost";
$username = "username";
$password = "password";
$dbname = "myDB";

// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$conn) {
    die(
"Connection failed: " . mysqli_connect_error());
}

$sql = "INSERT INTO MyGuests (firstname, lastname, email)
VALUES ('John', 'Doe', 'john@example.com')"
;

if (
mysqli_query($conn, $sql)) {
   
$last_id = mysqli_insert_id($conn);
    echo
"New record created successfully. Last inserted ID is: " . $last_id;
} else {
    echo
"Error: " . $sql . "<br>" . mysqli_error($conn);
}

mysqli_close($conn);
?>
up
-9
Steve Bond
20 years ago
If you use this function after doing an INSERT ... SELECT to insert multiple rows at once, you get the autonumber ID of the *first* row added by the INSERT.

e.g. if there are 4 records in table 'init' that have column 'type' = 2
I want to add these 4 records to table 'game'
Table game has an autonumber column 'game_id' that is currently at 32.

If I do this query:

INSERT INTO game (type, players, rounds)
SELECT type, players, rounds FROM init
WHERE type = 2

Then mysql_insert_id() will return 33, not 36.
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