The color value (3rd argument) for transparency is "none".
Imagick::newImage
(PECL imagick 2, PECL imagick 3)
Imagick::newImage — Creates a new image
Descrierea
Creates a new image and associates ImagickPixel value as background color
Parametri
-
cols -
Columns in the new image
-
rows -
Rows in the new image
-
background -
The background color used for this image
-
format -
Image format. This parameter was added in Imagick version 2.0.1.
Valorile întoarse
Întoarce true în caz de succes.
Erori/Excepții
Emite ImagickException în caz de eroare.
Istoricul schimbărilor
| Versiune | Descriere |
|---|---|
| PECL imagick 2.1.0 | Now allows a string representing the color as the third parameter. Previous versions allow only an ImagickPixel object. |
Exemple
Example #1 Using Imagick::newImage():
Create a new image and display it.
<?php
$image = new Imagick();
$image->newImage(100, 100, new ImagickPixel('red'));
$image->setImageFormat('png');
header('Content-type: image/png');
echo $image;
?>
add a note
User Contributed Notes 3 notes
christian dot reinecke at web dot de ¶
15 years ago
jfalner1 at gmail dot com ¶
9 years ago
As it isn't obvious, the cols and rows arguments correspond to the width and height of the new image, expressed in pixels. Example #1 would generate a 100 pixel by 100 pixel image.
Eduard Sukharev ¶
8 years ago
It's not obvious and may be related only to some specific versions of ImageMagick (tested only for 6.7.7 and 6.8.9), but $cols and $rows must be a positive non-zero value.
<?php
$image = new Imagick();
$image->newImage(0, 100, new ImagickPixel('red'));
$image->setImageFormat('png');
file_put_contents('image.png', $image);
?>
In this case imagemagick will crash without throwing any exception and you'll get something along the lines (in your apache error log or console output):
unable to acquire cache view `No such file or directory' @ fatal/cache-view.c/AcquireAuthenticCacheView/121.
This might be the case when you calculate $cols and $rows (say, based on user input and predefined target image DPI):
<?php
$image = new Imagick();
$img->newImage($userInput->getWidth() * $defaultPpi, $userInput->getHeight() * $defaultPpi, new ImagickPixel('white'));
?>
In this case if user requested image with 0.006 width (in inches), the code would work for $defaultPpi = 300 ppi, but would crash for
$defaultPpi = 72 ppi
