Imagick::scaleImage

(PECL imagick 2, PECL imagick 3)

Imagick::scaleImage — Scales the size of an image

Descrierea

public Imagick::scaleImage ( int $cols , int $rows , bool $bestfit = false , bool $legacy = false ) : bool

Scales the size of an image to the given dimensions. The other parameter will be calculated if 0 is passed as either param.

Notă: Comportamentul parametrului bestfit s-a schimbat în Imagick 3.0.0. Anterior acestei versiuni în cazul dimensiunilor 400x400, o imagine cu dimensiunile 200x150 ar fi rămas neschimbată. În Imagick 3.0.0 și versiunile ulterioare imaginea va fi mărită la dimensiunile 400x300 deoarece aceasta este "cea mai bună potrivire" pentru dimensiunile date. Dacă parametrul bestfit este utilizat, trebuie furnizate atât lățimea, cât și înălțimea.

Parametri

cols
rows
bestfit

Valorile întoarse

Întoarce true în caz de succes.

Erori/Excepții

Emite ImagickException în caz de eroare.

Istoricul schimbărilor

Versiune	Descriere
PECL imagick 2.1.0	Added optional fit parameter. This method now supports proportional scaling. Pass zero as either parameter for proportional scaling.

Exemple

Example #1 Imagick::scaleImage()


<?php
function scaleImage($imagePath) {
    $imagick = new \Imagick(realpath($imagePath));
    $imagick->scaleImage(150, 150, true);
    header("Content-Type: image/jpg");
    echo $imagick->getImageBlob();
}

?>

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User Contributed Notes 6 notes

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benford at bluhelix dot com ¶

15 years ago


If anyone finds "The other parameter will be calculated if 0 is passed as either param. " to be a bit confusing, it means approximately this:

<?php
$im = new Imagick('example.jpg');
$im->scaleImage(300, 0);
?>

This scales the image such that it is now 300 pixels wide, and automatically calculates the height to keep the image at the same aspect ratio.

<?php
$im = new Imagick('example.jpg');
$im->scaleImage(0, 300);
?>

Similarly, this example scales the image to make it 300 pixels tall, and the method automatically recalculates the image's height to maintain the aspect ratio.

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vincent dot hoen at gmail dot com ¶

17 years ago


Here is an easy way to resize an animated gif : 

$picture = new Imagick('animated_gif.gif');

foreach($picture as $frame){
    $frame->scaleImage($width, $height);
}

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octave at web dot de ¶

15 years ago


When using the "fit = true" option, the image will only scale down, but never scale up:

<?php
$im = new Imagick('1600x1200.jpg');

$im->scaleImage(2000, 1500, true); // => 1600x1200

$im->scaleImage(1000, 500, true); // => 666x500
?>

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agamemnus at flyingsoft dot pw ¶

10 years ago


Warning: this will blur your edges in possibly unexpected ways. For better control, use resizeImage, instead.

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clickconvert at gmail dot com ¶

11 years ago


Need to resize portrait and landscape images (and convert to 72ppi)? These will fit an area of 800x600 without distorting, no matter how tall or wide.



<?php

    $img = new Imagick($img_loc.$file);

    $img->setImageResolution(72,72); 

    $img->resampleImage(72,72,imagick::FILTER_UNDEFINED,1);

    $img->scaleImage(800,0);

    $d = $img->getImageGeometry(); 

    $h = $d['height']; 

    if($h > 600) {

    $img->scaleImage(0,600);

    $img->writeImage($resized_loc.$file);

    } else {

    $img->writeImage($resized_loc.$file);

    }

    $img->destroy();

?>

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-5

peter at icb dot at ¶

15 years ago


If using the fit-parameter this function sometimes seems not to work when one of the two sizes (width or height) is the same size as the image has. For example:

<?php
$image = new Imagick('800x480.jpg');
$image->scaleImage(640, 480, true);

// $image is still 800x480
?>

You have to calculate the new sizes yourself and use false for $fit in this case.

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