Loose checking returns some crazy, counter-intuitive results when used with certain arrays. It is completely correct behaviour, due to PHP's leniency on variable types, but in "real-life" is almost useless.
The solution is to use the strict checking option.
<?php
// Example array
$array = array(
'egg' => true,
'cheese' => false,
'hair' => 765,
'goblins' => null,
'ogres' => 'no ogres allowed in this array'
);
// Loose checking -- return values are in comments
// First three make sense, last four do not
in_array(null, $array); // true
in_array(false, $array); // true
in_array(765, $array); // true
in_array(763, $array); // true
in_array('egg', $array); // true
in_array('hhh', $array); // true
in_array(array(), $array); // true
// Strict checking
in_array(null, $array, true); // true
in_array(false, $array, true); // true
in_array(765, $array, true); // true
in_array(763, $array, true); // false
in_array('egg', $array, true); // false
in_array('hhh', $array, true); // false
in_array(array(), $array, true); // false
?>
in_array
(PHP 4, PHP 5, PHP 7)
in_array — 값이 배열 안에 존재하는지 확인
인수
-
needle -
찾을 값.
Note:
needle이 문자열이면, 대소문자를 구분하여 비교합니다. -
haystack -
배열.
-
strict -
세번째 인수
strict를TRUE로 설정하면, in_array() 함수는haystack안에서needle의 자료형도 확인합니다.
반환값
needle을 배열에서 찾으면 TRUE를, 아니면 FALSE를
반환합니다.
변경점
| 버전 | 설명 |
|---|---|
| 4.2.0 |
needle이 배열일 수 있습니다.
|
예제
Example #1 in_array() 예제
<?php
$os = array("Mac", "NT", "Irix", "Linux");
if (in_array("Irix", $os)) {
echo "Got Irix";
}
if (in_array("mac", $os)) {
echo "Got mac";
}
?>
in_array()가 대소문자를 구분하므로 두번째 조건은 실패하고, 위 프로그램은 다음을 출력합니다:
Got Irix
Example #2 in_array()에 strict 예제
<?php
$a = array('1.10', 12.4, 1.13);
if (in_array('12.4', $a, true)) {
echo "'12.4' found with strict check\n";
}
if (in_array(1.13, $a, true)) {
echo "1.13 found with strict check\n";
}
?>
위 예제의 출력:
1.13 found with strict check
Example #3 in_array()에 needle로 배열
<?php
$a = array(array('p', 'h'), array('p', 'r'), 'o');
if (in_array(array('p', 'h'), $a)) {
echo "'ph' was found\n";
}
if (in_array(array('f', 'i'), $a)) {
echo "'fi' was found\n";
}
if (in_array('o', $a)) {
echo "'o' was found\n";
}
?>
위 예제의 출력:
'ph' was found 'o' was found
참고
- array_search() - 주어진 값으로 배열을 검색하여 성공시 해당하는 키를 반환
- isset() - 설정된 변수인지 확인
- array_key_exists() - 주어진 키와 인덱스가 배열에 존재하는지 확인
add a note
User Contributed Notes 8 notes
beingmrkenny at gmail dot com ¶
13 years ago
Julian Sawicki ¶
1 year ago
Here is a recursive in_array function:
<?php
$myNumbers = [
[1,2,3,4,5],
[6,7,8,9,10],
];
$array = [
'numbers' => $myNumbers
];
// Let's try to find number 7 within $array
$hasNumber = in_array(7, $array, true); // bool(false)
$hasNumber = in_array_recursive(7, $array, true); // bool(true)
function in_array_recursive(mixed $needle, array $haystack, bool $strict): bool
{
foreach ($haystack as $element) {
if ($element === $needle) {
return true;
}
$isFound = false;
if (is_array($element)) {
$isFound = in_array_recursive($needle, $element, $strict);
}
if ($isFound === true) {
return true;
}
}
return false;
}
Armands Rieksti ¶
1 year ago
I'd like to point out that, if you're using Enum data structures and want to compare whether an array of strings has a certain string Enum in it, you need to cast it to a string.
From what I've tested, the function works correctly:
if the array is filled with strings and you're searching for a string;
if the array is filled with Enums and you're searching for an Enum.
rhill at xenu-directory dot net ¶
15 years ago
I found out that in_array will *not* find an associative array within a haystack of associative arrays in strict mode if the keys were not generated in the *same order*:
<?php
$needle = array(
'fruit'=>'banana', 'vegetable'=>'carrot'
);
$haystack = array(
array('vegetable'=>'carrot', 'fruit'=>'banana'),
array('fruit'=>'apple', 'vegetable'=>'celery')
);
echo in_array($needle, $haystack, true) ? 'true' : 'false';
// Output is 'false'
echo in_array($needle, $haystack) ? 'true' : 'false';
// Output is 'true'
?>
I had wrongly assumed the order of the items in an associative array were irrelevant, regardless of whether 'strict' is TRUE or FALSE: The order is irrelevant *only* if not in strict mode.
leonhard dot radonic+phpnet at gmail dot com ¶
2 years ago
I got an unexpected behavior working with in_array. I'm using following code:
<?php
// ...
$someId = getSomeId(); // it gets generated/fetched by another service, so I don't know what value it will have. P.S.: it's an integer
// The actual data in my edge-case scenario:
// $someId = 0;
// $anyArray = ['dataOne', 'dataTwo'];
if (in_array($someId, $anyArray)) {
// do some work
}
// ...
?>
With PHP7.4, in_array returns boolean true.
With PHP8.1, in_array returns boolean false.
It took me quite some time to find out what's going on.
thomas dot sahlin at gmail dot com ¶
15 years ago
If you're creating an array yourself and then using in_array to search it, consider setting the keys of the array and using isset instead since it's much faster.
<?php
$slow = array('apple', 'banana', 'orange');
if (in_array('banana', $slow))
print('Found it!');
$fast = array('apple' => 'apple', 'banana' => 'banana', 'orange' => 'orange');
if (isset($fast['banana']))
print('Found it!');
?>
